Answer:
It is a good Estimator of the Population Mean because the distribution of the sample midrange is just same as the distribution of the random variable.
Step-by-step explanation: from the table,
Minimum value = 34
maximum values = 1084
The sample mid-range can be computed as:
(Min.value + max.value)/2
(34 + 1084)/2
Sample mid-range = 55
The sample midrange uses only a small portion of the data, but can be heavily affected by outliers.
It provides information about the skewness and heavy-tailedness of the distribution which is just same as the distribution of the random variable.
The nature of this distribution is not intuitive but the Central Limit in which it will approach a normal distribution for large sample size.
The answer is: C - x^3 + 27
A suitable probability app shows the 1st percentile to be at about 11040 pages.
_____
The app shown has an error in the first decimal digit. The number is closer to 11040.82301. We expect the manufacturer would round to the nearest 10 or 50 or 100 in advertising.
I do not have the graph that you are referencing from this question to, but I can help you get led to the right answer. If the teacher exhibits the most variable year to year performance over a 5 year span, then the graph must show unstable fluctuating of figures. Those who are least variable would have a steady line going up or down or maybe even just straight.