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anygoal [31]
3 years ago
15

Form a third degree polynomial function with real coefficients such that 8+i and 7 are zeros.

Mathematics
1 answer:
Lyrx [107]3 years ago
3 0
The zeros of the equation are <span>8+i and 7. however since this is a third degree polynomial, the other root missing is the conjugate of the imaginary term 8-i, which is 8 +i. We multiply then ( x- 8 - i) *( x- 7)* (x - 8 + i).The expansion is  (x2 - 16x + 1 --1 ) *(x-7) = </span><span>(x2 - 16x + 2 )(x-7) = x3 -7 x2 -16x2 +112 x +2x -14 = x3 -23 x2 + 114 x -14</span>
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Determine if the statement is possible(p) or impossible(i).
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Step-by-step explanation:

53+118+9=180

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1 year ago
Why are 7 and 2 like terms? help please!!
bazaltina [42]

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7 0
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3 years ago
From 1960 to 1980 , the consumer price index (cpi) increased from 29.6 to 82.4. If a frozen chicken pie cost $0.28 in 1960 and t
mojhsa [17]

CPI in 1960 = 29.6

CPI in 1980 = 82.4

Growth (%) in CPI = \frac{\text{CPI in 1980 - CPI in 1960}}{\text{CPI in 1960}} × 100

⇒ Growth (%) in CPI = \frac{82.4-29.6}{29.6} × 100

⇒ Growth (%) in CPI = 178.3783.. %

⇒ Growth (%) in CPI = 178.4%

Now, we know that price of frozen chicken pie in 1960 = $0.28

Also, we know that over 1960 to 1980, frozen chicken pie price grew at the same rate as CPI

Hence, Price of Chicken Pie in 1980 = Price of Chicken Pie in 1960 × (1 + Growth in CPI)

⇒ Price of Chicken Pie in 1980 = 0.28 × (1 + 178.4%)

⇒ Price of Chicken Pie in 1980 = 0.28 + (0.28 × 178.4%)

⇒ Price of Chicken Pie in 1980 = 0.28 + 0.49952

⇒ Price of Chicken Pie in 1980 = 0.28 + 0.50

⇒ Price of Chicken Pie in 1980 = $0.78

Hence, price of chicken pie in 1980 would be ~$0.78

8 0
3 years ago
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abruzzese [7]

Answer:

a₆ = 13x + 31

Step-by-step explanation:

The nth term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

Here a₁ = 3x + 1 and d = 2x + 6 , then

a₆ = 3x + 1 + 5(2x + 6)

    = 3x + 1 + 10x + 30

    = 13x + 31

7 0
3 years ago
Read 2 more answers
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