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Anettt [7]
3 years ago
10

There are 28 student desks in Ms. Johnson’s. Each desk measures 26.17 inches long. If you were to line up all the desks end-to-e

nd, how long would all the desks be?
Mathematics
1 answer:
trasher [3.6K]3 years ago
4 0

Answer:

732.76

Step-by-step explanation:

There are 28 desks and each is 26.17. The word "each" signifies multiplication. Formula  - 26.17 x 28  or ; inches x desks

Hope this helps :)

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I need help with this math question on my study guide!
dalvyx [7]
Sadly is right.  You must have practiced this stuff in middle school
until it was coming out of your ears.  Fortunately, you have a chance
to relearn it now.  You should do that ... it'll be important in any math
course you ever take.

'm' is the slope of the line on the graph.

The slope is

                (the change in 'y' between any two points on the line)
divided by
               (the change in 'x' between the same two points).

You can choose any two points on the line, and the slope is always the same.

To make it easy, look at the two points on this graph where the line crosses
the x-axis and the y-axis.

Going between these two points ...
-- the line goes up, from  y=0  to  y=4.  The change in 'y' is  4 .
-- the line goes to the right, from  x=-2  to  x=0.  The change in 'x' is  2 .

           'm' = the slope  =  (4)/(2)  =  2 .

The  "y-intercept"  is the place where the line crosses the y-axis.
On this graph, that's the point where  y=4 .

The equation of EVERY straight line on ANY graph is:

                 Y  =  (the slope) times 'x'  +  (the y-intercept) .

So the equation of THIS line on THIS graph is

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5 0
3 years ago
Find the uncertainty in a calculated average speed from the measurements of distance and time. Average speed depends on distance
zzz [600]

Answer:

\frac{\Delta v}{v}=0.426

Step-by-step explanation:

you have that the average sped is given by the following formula:

v(x,t)=\frac{x}{t}

The uncertainty formula for a division is given by:

\frac{\Delta v}{v}=\sqrt{(\frac{\Delta x}{x})^2+(\frac{\Delta t}{t})^2}        (1)

Δv: uncertainty in speed

Δx: uncertainty in the distance = 0.9m

Δt: uncertainty in time = 0.7s

x: distance = 8.1m

t: time = 1.7s

You replace the values of all parameters in the equation (1):

\frac{\Delta v}{v}=\sqrt{(\frac{0.9}{8.1})^2+(\frac{0.7}{1.7})^2}\\\\\frac{\Delta v}{v}=0.426

Hence, the relation between the uncertainty in the average velocity is 0.426

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3 years ago
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IRINA_888 [86]

Answer:

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