-ab>0 is the answer cause the others make 0 not to be simplified
Answer:
Step-by-step explanation:
Answer:
ρ_air = 0.15544 kg/m^3
Step-by-step explanation:
Solution:-
- The deflated ball ( no air ) initially weighs:
m1 = 0.615 kg
- The air is pumped into the ball and weight again. The new reading of the ball's weight is:
m2 = 0.624 kg
- The amount of air ( mass of air ) pumped into the ball can be determined from simple arithmetic between inflated and deflated weights of the ball.
m_air = Δm = m2 - m1
m_air = 0.624 - 0.615
m_air = 0.009 kg
- We are to assume that the inflated ball takes a shape of a perfect sphere with radius r = 0.24 m. The volume of the inflated ( air filled ) ball can be determined using the volume of sphere formula:
V_air = 4*π*r^3 / 3
V_air = 4*π*0.24^3 / 3
V_air = 0.05790 m^3
- The density of air ( ρ_air ) is the ratio of mass of air and the volume occupied by air. Expressed as follows:
ρ_air = m_air / V_air
ρ_air = 0.009 / 0.05790
Answer: ρ_air = 0.15544 kg/m^3
Answer:
107/21
Step-by-step explanation:
re - phrase the question algebraically:
-14/3 + y = 3/7
LCM of 3 and 7 = 21
-98/21 + y = 9/21
what should be added to -98 to make 9?
answer: 107
therefore answer: 107/21
Hope this helps.
Good Luck
Answer:
The answer is D.
Step-by-step explanation:
The difference between each term is 4.
-2 - (-6) = 4
2 - (-2) = 4
6 - 2 = 4
10 - 6 = 4
