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NemiM [27]
3 years ago
11

Can someone help me please ?

Mathematics
1 answer:
e-lub [12.9K]3 years ago
8 0

Answer:

=

Step-by-step explanation:

1. The square root of 4 is 2 because 2^2 = 4.

2. The cube root of 8 is 2 because 2^3 = 2* 2 * 2 = 8.

3. 2 and 2 are equal.

Therefore, the correct symbol is =.

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Ab is perpendicular to cd how many 90 angles are formed by the intersection
Shtirlitz [24]
Only one unless it goes across than2
3 0
3 years ago
The perimeter of a rectangle is 194. The length is 25 more than 5 times the width. Find the dimensions.
Juli2301 [7.4K]

Answer:

  • 12 and 85

Step-by-step explanation:

<h3>Given</h3>
  • P = 194
  • l = 5w + 25
  • l = ?, w = ?
<h3>Solution</h3>

<u>Perimeter formula</u>

  • P = 2(l + w)

<u>Substitute and solve for w:</u>

  • 194 = 2(5w +25 + w)
  • 194 = 12w + 50
  • 12w = 144
  • w = 144/12
  • w = 12

<u>Find the length:</u>

  • l = 5*12 + 25 = 85
4 0
3 years ago
What is N in -2n+2(3n+14)=-20​
seraphim [82]

Answer:

To solve for n you need to get it by itself

First you want to distribute your 2 through the (3n+14)

-2n+6n+28=-20 (2*3n+2*14= 6n+28)

Now you want to combine any like terms if possible

4n+28=-20 (-2n+6n=4n, both like terms)

Then you want to subtract -28 from both sides

4n=-48 (28-28=0, -20-28=-48)

Lastly you want to divide both sides by 4

n=-12 (4n/4=n, -48/4= -12)

4 0
3 years ago
Damian set up a bucket to catch the raindrops. Buckets can hold 1 gallon. If each raindrop is made of about 1/90 fluid ounces of
LuckyWell [14K]
Since there are 128 fluid ounces in a gallon and a raindrop is 1/90, you have to multiply 128 by 90. Since it takes 90 raindrops to get to a whoke fl oz, and you need 128, you hae to multiply:
128×90=11,520
It takes 11,520 raindrops to fill the bucket.
4 0
3 years ago
N2 + 3H2 → 2NH3
alukav5142 [94]

Step-by-step explanation:

1. N2 + 3H2 → 2NH3

How many moles of NH3 could you make with 4.2021 g of N2?

From the reaction;

1 mol of N2 produces 2 mol of NH3

1 mol of N2 = 14g of N2

14g of N2 produces 2 mol of NH3

4.2021 g of N2 produces x mol of NH3

14 = 2

4.2021 = x

x = 4.2021  * 2 / 14 = 0.6003 mol of NH3

2. 2Na + Cl2 → 2NaCl

How many moles of Cl2 do you need to use in order to react with 34.485 g of Na?

From the equation of the reaction;

2 mol of Na reacts with 1 mol of Cl2

1 mol of Na = 23g of Na

2 mol of Na - 46g of Na

46g of Na reacts with 1 mol of Cl2

4.485 g of Na reacts with x mol of Cl2

46 = 1

4.485 = x

x = 4.485 * 1 / 46 = 0.0975 mol of Cl2

3. H2SO4 + 2NaNO2 → 2HNO2 + Na2SO4

How many grams of NaNO2 do you need in order to make 24.14714 g of Na2SO4?

From the reaction;

2 mol of NaNO2 produces 1 mol of Na2SO4

2 mol of NaNO2 = 68.995 g/mol * 2mol = 137.99g

1 mol of Na2SO4 = 142.04 g

137.99g of NaNO2 produces 142.04 g of Na2SO4

xg of NaNO2 produces 24.14714 g of Na2SO4?

137.99 = 142.04

x = 24.14714

x = 24.14714 * 137.99 / 142.04 = 23.459g

4. 2Na + 2H2O → 2NaOH + H2

How many grams of NaOH could you make with 8.0465 g of Na?

From the reaction;

2 mol of Na produces 2 mol of NaOH

2 mol of Na = 23g/mol * 2mol = 46g

2 mol of NaOH = 40g/mol * 2 = 80g

46 g of Na produces 80g of NaOH

8.0465 g of Na produces xg of NaOH

46 = 80

8.0465 = x

x = 8.0465 * 80 / 46 = 13.994g

5. 2Mg + O2 → 2MgO  

If you are burning 5.8332 g of Mg, how many grams of MgO will this make?

From the reaction;

2 mol of Mg produces 2 mol of MgO

2 mol of Mg = 24 g/mol * 2mol = 48g

2 mol of MgO = 40.3 g/mol  * 2mol = 80.6g

48g of Mg produces 80.6 g  of MgO

5.8332 g of Mg produces xg of MgO

48 = 80.6

5.8332 = x

x = 5.8332 * 80.6 / 48   = 9.8g

6. FeCl3 + 3NaOH → Fe(OH)3 + 3NaCl

How many grams of NaCl could you make with 2.43306 g of FeCl3?

From the reaction;

1 mol of FeCl3 produces 3 mol of NaCl

1 mol of FeCl3 = 162.2 g

3 mol of NaCl = 58.44 g/mol * 3 mol = 175.32 g

162.2g of FeCl3 produces 175.32 g of NaCl

2.43306 g of FeCl3 produces xg of NaCl

162.2 = 175.32

2.43306 = x

x = 2.43306 * 175.32 / 162.2 = 2.63g

4 0
3 years ago
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