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kondor19780726 [428]
3 years ago
10

Ab is perpendicular to cd how many 90 angles are formed by the intersection

Mathematics
1 answer:
Shtirlitz [24]3 years ago
3 0
Only one unless it goes across than2
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Hot Shot Electronics is designing a packing box for its new line of Acoustical Odyssey speakers. The box is a rectangular prism
Whitepunk [10]
V= W × H × L
81000 = 30 × H × 45
81000 = 1350× H
81000/1350 = 1350/1350× H
H = 60 cm
8 0
3 years ago
What is the quotient if the dividend is 2286 and the divisor is 6
Anna11 [10]

Answer:

381

Step-by-step explanation:

2,286/6=381

Good luck!

8 0
3 years ago
I need help in math ;pmdjew2kedfheyuwikejhuwiqo
Licemer1 [7]

Answer:

30/343

Step-by-step explanation:

to find the volume of a rectangle you multiply all three fraction

5/7*3/7*2/7

5/7*3/7=15/49

15/49*2/7=30/343

30/343

5 0
3 years ago
A triangle has angle measures 23° and 35°. What is the measure of the third angle ?
frozen [14]
23 + 35 + A=180
58 + a =180
-58         -58
-------------------
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7 0
3 years ago
Read 2 more answers
A student takes a driving test until it is passed.
Leya [2.2K]

Answer:

The probability that the test is taken an even number of times is 0.30.

Step-by-step explanation:

The probability that a student passes the driving test at any attempt is,

<em>p</em> = 4/7.

The event of a student passing in any attempt is independent of each other.

The probability that the test is taken an even number of times is:

P (even number of tests) = P (Passing in the 2nd attempt)

                                                  + P (Passing in the 4th attempt)

                                                       + P (Passing in the 6th attempt) ...

If a student passed in the 2nd attempt it implies that he failed in the first.

Then,  P (Passing in the 2nd attempt) = (\frac{3}{7}) \times (\frac{4}{7})

Similarly, P (Passing in the 4th attempt) = (\frac{3}{7})^{3} \times (\frac{4}{7}), since he failed in the first 3 attempts.

And so on.

Compute the probability of an even number of tests as follows:

P (even number of tests) = (\frac{3}{7}) \times (\frac{4}{7})+(\frac{3}{7})^{3} \times (\frac{4}{7})+(\frac{3}{7})^{5} \times (\frac{4}{7})+...

The result follows a Geometric progression for infinite values.

The sum of infinite GP is:

S=\frac{a}{1-r^{2}}

The probability is:

P (even number of tests) = (\frac{3}{7}) \times (\frac{4}{7})+(\frac{3}{7})^{3} \times (\frac{4}{7})+(\frac{3}{7})^{5} \times (\frac{4}{7})+...

                                          =\frac{(\frac{3}{7})(\frac{4}{7} ) }{1-(\frac{3}{7})^{2}}\\=\frac{12}{49}\times\frac{49}{40}\\  =\frac{12}{40}\\ =0.30

Thus, the probability that the test is taken an even number of times is 0.30.

7 0
3 years ago
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