The values of a, b, and c are -4,0 and 0 and the parabola opens downward with y-intercept (0,0).
we have
y=-4x^2
<h3>What is the standard form of the quadratic equation?</h3>
The quadratic equation in standard form is equal to
ax^2+bx+c=0
So,In this problem
a=-4, b=0 and c=0
The y-intercept is the value of y when the value of x is equal to zero
y=-4(0)^2=0
The y-intercept is the point (0,0)
The coefficient a is negative, therefore the parabola opens down.
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Given (5/3)y = (1/4)x - 3, we rearrange these terms so that the equation appears like Ax + By = C:
-(1/4)x + (5/3)y = -3 This is the equation in "standard form."
Answer:
x=−8+√86 or x=−8−√86
or
344
Step-by-step explanation:
Let's solve your equation step-by-step.
x2+16x=22
Answer:
x>2
Step-by-step explanation:
Answer:
see i know the answer to the half