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ahrayia [7]
3 years ago
5

Sarah has a cell phone plan that charges $0.12 per minute plus a monthly fee of $21.00. She budgets $65.50 per month for total c

ell phone expenses without taxes. What is the maximum number of minutes Sarah could use her phone each month in order to stay within her budget?
Mathematics
1 answer:
kirill115 [55]3 years ago
6 0

Answer:

собак в гавне гандонов дешовых псин

Step-by-step explanation:

phone expenses without taxes. What is the maximum number of minutes Sarah could use her phone each month in order to stay within her budget?phone expenses without taxes. What is the maximum number of minutes Sarah could use her phone each month in order to stay within her budget?phone expenses without taxes. What is the maximum number of minutes Sarah could use her phone each month in order to stay within her budget?phone expenses without taxes. What is the maximum number of minutes Sarah could use her phone each month in order to stay within her budget?phone expenses without taxes. What is the maximum number of minutes Sarah could use her phone each month in order to stay within her budget?phone expenses without taxes. What is the maximum number of minutes Sarah could use her phone each month in order to stay within her budget?phone expenses without taxes. What is the maximum number of minutes Sarah could use her phone each month in order to stay within her budget?phone expenses without taxes. What is the maximum number of minutes Sarah could use her phone each month in order to stay within her budget?phone expenses without taxes. What is the maximum number of minutes Sarah could use her phone each month in order to stay within her budget?phone expenses without taxes. What is the maximum number of minutes Sarah could use her phone each month in order to stay within her budget?phone expenses without taxes. What is the maximum number of minutes Sarah could use her phone each month in order to stay within her budget?phone expenses without taxes. What is the maximum number of minutes Sarah could use her phone each month in order to stay within her budget?phone expenses without taxes. What is the maximum number of minutes Sarah could use her phone each month in order to stay within her budget?

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Consider the following system of equations. StartLayout Enlarged left-brace 1st row negative 10 x squared minus 10 y squared = n
ziro4ka [17]

These 2 equations has no solution and the equations are independent of each other.

<u>Step-by-step explanation:</u>

-10x² -10y² = -300 ----a

5x² + 5y² = 150 ---- b

While trying to solve this,

We can multiply the eq. b by 2 so we will get eq. c and then add to eq. a we will get 0 as the solution.

10x² + 10y² = 300 ----c

-10x² -10y² = -300 ---a

Everything cutoff, we will get 0, and there is no solution to these equations.

4 0
3 years ago
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A snowstorm lasted for three days. Durning the storm, 8 inches of snow fell on the first day, 6 inches of snow fell on the secon
TiliK225 [7]

Answer:

Basically we need to add all of the inches

Step-by-step explanation:

so...

8 inch ( first day ) + 6 inch ( second day) + 9 inch ( third day )

add all those inches together what do you get?

23 inches in total. So altogether 23 inches of snow fell during the 3-day storm

7 0
3 years ago
PLZ HELP!! In the following figure, triangle ABC is a right triangle, and mA = 42°. Find the value of n°. Note: the figure is no
TEA [102]

Answer:

n = 132

Step-by-step explanation:

The external angle of a triangle is equal to the sum of the 2 opposite interior angles.

n is an exterior angle of the triangle, thus

n = 90 + 42 = 132

3 0
3 years ago
A rectangular plot of farmland will be bounded on one side by a river and on the other three sides by a single-strand electric f
Tpy6a [65]
<span>2x+y=400 A=xy area of farmland y=400-2x A=400x-2x^2 A'(x)= 400 -4x derivative of area with respect to x 0=400-4x find out where f ' equals 0 4x=400 x=100 A'(x)= 400 -4x A''(x)= -4 check 2nd derivative. if negative then relative max at x=100 2x+y=400 y=200 dimensions 100x200 hope it helped</span>
7 0
3 years ago
PLS HALP I'm stuck on number 31
Marta_Voda [28]
There are 2 possibilities for where A can be: one where C is 30° (and A is 60°) and another where C is 60° (and A is 30°). Since it's not specified, we can find both.

30°:
drawing the triangle on a graph, you can see that point C is 4 units above point B, so we know that one side of the triangle is 4. Once we find the other "leg" of the triangle (the one that's parallel to the x-axis), we can just add that value to B to find the x coordinate of A.
If angle C is 30°, using the side ratios of a 30-60-90 triangle, that side is "a√3", and the side we're looking for is a. So, to find a, we just divide 4 by √3. In that case, point A is 4/(√3) units to the right of -2√3. We can rationalize 4/(√3) like this:

(4√3)/3

and then add that to 2√3:

(4√3)/3 + -2√3

(4√3)/3 + (-6√3)/3 = (-2√3)/3

We know that the x-coordinate of A is (-2√3)/3, and the y-coordinate is -1 because B is a right angle and we're just moving horizontally. So, if C is 30° and A is 60°, point A is at ((-2√3)/3, -1).

60°:
in this case, the leg we know is "a" and the leg we're looking for is "a√3". So, we can multiply 4 by √3 to get the distance from B:

4 x √3 = 4√3

4√3 + -2√3 = 2√3

So the x-coordinate of A here is 2√3, and the y-coordinate is still -1: (2√3, -1).

hope that helps! if you liked this answer please rate it as brainliest!! thank you!!!

8 0
3 years ago
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