What do you need??????????????
Answer:
Step-by-step explanation:
㏒ 3+㏒(x+2)=1
㏒3(x+2)=1
3(x+2)=10^1
3x+6=10
3x=10-6=4
x=4/3
so A
3.
![log_{2}x+log_{2}(x+2)=3\\or~log_{2}[x(x+2)]=3\\x(x+2)=2^3\\x^2+2x-8=0\\x^2+4x-2x-8=0\\x(x+4)-2(x+4)=0\\(x+4)(x-2)=0\\x=2,-4\\x=-4 ~is~an~extraneous~solution.\\B](https://tex.z-dn.net/?f=log_%7B2%7Dx%2Blog_%7B2%7D%28x%2B2%29%3D3%5C%5Cor~log_%7B2%7D%5Bx%28x%2B2%29%5D%3D3%5C%5Cx%28x%2B2%29%3D2%5E3%5C%5Cx%5E2%2B2x-8%3D0%5C%5Cx%5E2%2B4x-2x-8%3D0%5C%5Cx%28x%2B4%29-2%28x%2B4%29%3D0%5C%5C%28x%2B4%29%28x-2%29%3D0%5C%5Cx%3D2%2C-4%5C%5Cx%3D-4%20~is~an~extraneous~solution.%5C%5CB)
3/5 = 9/15 = 36/60
2/3 = 10/15 = 40/60
0.65 = 65/100 = 13/20 = 39/60
Therefor, the answer is 3/5, 0.65, 2/3.
Answer:
1) (2, 3)
2) (2, -5).
Step-by-step explanation:
2x – y = 1
2x +2y = 10 Subtract to eliminate the 2x:
2x - 2x - y - 2y = 1 - 10
-3y = -9
y = 3.
Plug this into the first equation:
2x - 3 = 1
2x = 4
x = 2.
2)
5x – y =15
x + y = -3 Adding to eliminate y:
5x + x - y + y = 15 + -3
6x = 12
x = 2
Plug this into the first equation:
5(2) - y = 15
-y = 15 - 10 = 5
y = -5.
Statement Problem: P, Q and R are three buildings. A car began its journey at P, drove to Q, then to R and returned to P. The bearing of Q from P is 058° and R is due east of Q. PQ = 114 km and QR = 70 km. ( Draw a clearly labelled diagram to represent the above information.
Solution: