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OverLord2011 [107]
2 years ago
13

I added 3/4 + 1/5 and got 4/9 " does it make sense?

Mathematics
2 answers:
cupoosta [38]2 years ago
8 0

Answer:

No, it does not. The answer is 19/20

Step-by-step explanation:

3/4 + 1/5 = ?

3         1              15           4              19

----- + ----      =  --------   +  ------   =  ----------

4         5            20            20           20

1) Multiply the denominators by eachother and cross multiply the apposite numerator and denominator.  4 x 5 = 20. 3 x 5 = 15. 4 x 1 = 4

3) Add together

masya89 [10]2 years ago
4 0
<h3 /><h3>\frac{3}{4}  +  \frac{1}{5}  =  \frac{4}{9}  \\  \frac{3 \times 5}{4 \times 5}  +  \frac{1 \times 4}{5 \times 4}  =  \frac{4}{9}  \\  \frac{15 + 4}{20}  =  \frac{4}{9}  \\  \frac{19}{20} ≠ \frac{4}{9}</h3>

THIS SHOWS THAT YOUR ANSWER IS NOT CORRECT.

<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em>

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Will someone please help me with this
musickatia [10]

Answer:

B. f(-5) = -70

Step-by-step explanation:

f(-5)= 10(-5) - 20

f(-5) = -50 - 20

f(-5) = -70

3 0
3 years ago
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I keep trying to use the Pythagorean Theorem to find the missing sides length but it comes to a -31 then an Error when square ro
OverLord2011 [107]
Diagonal of the left triangle = ((8)^2+(7)^2)^0.5= (113)^0.5
x =( 12^2 -(113)^0.5)^2))^0.5=( 144- 113)^0.5= (31)^0.5= 5.57


For ur working, ur mistake lies in the line : x^2+12^2=10.6^2
It shld be 12^2= x^2+10.6^2
3 0
4 years ago
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fred thinks of a number that is greater than 110 and less than 120. he can make his number with same number of hundreds,tens and
VashaNatasha [74]

The number Fred thinks of is 111

<em><u>Solution:</u></em>

Given that, Fred thinks of a number that is greater than 110 and less than 120

He can make his number with same number of hundreds,tens and ones

<em><u>To find: Fred's number</u></em>

Given that the number is greater than 110 and less than 120

The possible numbers are:

111 , 112, 113, 114, 115, 116, 117, 118, 119

But he can make his number with same number of hundreds,tens and ones

So the numbers in ones, tens and hundreds place are same

So the only possible number is 111

Thus the number Fred thinks of is 111

8 0
4 years ago
if sarah rides her bike 5 miles north, then 3 miles east, what is the shortest distance she would have to travel to return to he
kykrilka [37]

Answer:

The answer to your question is the shortest distance is 5.83 mi

Step-by-step explanation:

Process

1.- We observe that the rides to north and after to east, so she is describing a right triangle where the shortest distance to come back to the starting point is the hypotenuse of that triangle.

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                                 c² = 5² + 3²

                                 c² = 25 + 9

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                                 c = 5.83 mi

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