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Cloud [144]
2 years ago
7

F(x)=5x-1; find f (-2), f (0), and f (x+1)

Mathematics
2 answers:
Phoenix [80]2 years ago
7 0

Answer:

f(-2) = -11

f(0) = -1

f(x+1)= f (x+1)=5x+4

Step-by-step explanation:

sergey [27]2 years ago
6 0
1 2 e Huhhhyeeaaaaaaahhhhhhhhhh
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Help please, thanks :)
tensa zangetsu [6.8K]

Answer:

60°

Step-by-step explanation:

Angle 1 is a vertical angle to 60° by the definition of a vertical angle.

8 0
3 years ago
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the vertex of this parabola is at (5,5). when the x-value is 6, the y-value is -1. what is the coefficient of the squared in the
zlopas [31]

Answer: OPTION D.

Step-by-step explanation:

The vertex form of a quadratic function is:

y= a(x - h)^2 + k

Where (h, k) is the vertex of the parabola and "a" is the coefficient of the squared in the parabola's equation.

We know that the vertex of this parabola is at (5,5) and we also know that when the x-value is 6, the y-value is -1.

Then  we can substitute values into  f (x) = a(x - h)^2 + k and solve for "a". This is:

-1= a(6- 5)^2 + 5\\\\-1=a+5\\\\-1-5=a\\\\a=-6

7 0
3 years ago
Which triangle is a translation of triangle x?
Vadim26 [7]

Answer:

B

Step-by-step explanation:

because x is 3 high and 2 across so is B

4 0
2 years ago
Read 2 more answers
The base of a triangle is 4cm longer than the altitude and it’s area is 16cm^2. Find the length of the base and the altitude [Pl
Rina8888 [55]

Answer:

The base = 8 cm and the altitude = 4 cm.

Step-by-step explanation:

b = a + 4  where b = base and a = the altitude.

Area = 1/2 * a * b = 16

Area = 1/2 * a * (a + 4) = 16

1/2 a^2 + 2a = 16

a^2 + 4a - 32 = 0

(a + 8)(a - 4) = 0

a = 4 .

b = 4+4 = 8.

8 0
2 years ago
Find the sample standard deviation:
zlopas [31]

Answer:

<h2>B. 7.1</h2>

Step-by-step explanation:

Given the sample data 2 6 15 9 11 22 1 4 8 19, before we can get the standard deviation, we need to first calculate the mean.

mean = 2 +6 +15 +9 +11 +22 +1 +4 +8 +19/10

mean = 97/10

mean = 9.7

Standard deviation for ungrouped data is expressed using the formula;

S = \sqrt{ \dfrac{\sum(x-\overline x)^2}{n-1} }

\overline x \ is\ the \ mean\\n \ is \ sample \ size

S = \sqrt{\frac{(2-9.7)^2+(6-9.7)^2+(15-9.7)^2+(9-9.7)^2+(11-9.7)^2+(22-9.7)^2+(1-9.7)^2+(4-9.7)^2+(8-9.7)^2+(19-9.7)^2}{10-1} }\\ S = \sqrt{\frac{(-7.7)^2+(-3.7)^2+(5.3)^2+(-0.7)^2+(1.3)^2+(12.3)^2+(-8.7)^2+(-5.7)^2+(-1.7)^2+(9.3)^2}{10-1} }\\\\S =  \sqrt{\dfrac{59.29+13.69+28.09+0.49+1.69+151.29+75.69+32.49+2.89+86.49}{10-1} }\\\\\\S =  \sqrt{\dfrac{452.1}{9} }\\\\S = \sqrt{50.23}\\ \\S = 7.08\\\\S \approx 7.1

<em>Hence the standard deviation of the sample data is 7.1</em>

7 0
2 years ago
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