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Mademuasel [1]
3 years ago
13

Pls give me an explanation on how to do this so I can do the other problems on my own​

Mathematics
2 answers:
galina1969 [7]3 years ago
8 0

Answer:

Everything on the left of the 0 is negative and everything to the right of 0 is positive

Step-by-step explanation:

zaharov [31]3 years ago
8 0

Answer:

-2

3

Step-by-step explanation:

This is because on the left it's negatif like -1,-2,-3

while in the right side it's positif which is 0,1,2,3,4,5

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pashok25 [27]

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4 0
3 years ago
What is the first step in evaluating the expression shown below?
Olegator [25]

Answer:

A

Step-by-step explanation:

because it is is parenthesis

8 0
3 years ago
Twice a number is one
sladkih [1.3K]

would the answers be 0.5? i'm not sure but i tried. have a great day.

cuz half (x2) of a number (x) is (=) one..

2x=1

0.5=x

0.5x2=1

3 0
3 years ago
Read 2 more answers
:)))) solve the following by factorizing: x^2-2x=120
stepladder [879]

Answer:

Step-by-step explanation:

x^2 - 2x = 120\\x^2 - 2x - 120 = 0

We have to find the factors of 120 that can either add up to or have a difference of 2.

The factors of 120 are:

\pm 1, 120, 2, 60, 3, 40, 4, 30, 5, 44, 6, 20, 8, 15, 10, 12...

The difference of 10 and 12 is 2. In the equation, since the 2 is negative, the larger number must be subtracted, so the factorized form is:

(x+10)(x-12)

3 0
3 years ago
An automobile manufacturer would like to know what proportion of its customers are not satisfied by the service provided by the
zheka24 [161]

Answer:

The sample size needed if the margin of error of the confidence interval is to be about 0.04 is 18.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Past studies suggest this proportion will be about 0.15

This means that p = 0.15

Find the sample size needed if the margin of error of the confidence interval is to be about 0.04

This is n when M = 0.04. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.15*0.85}{n}}

0.04\sqrt{n} = 1.96\sqrt{0.15*0.85}

\sqrt{n} = \frac{1.96\sqrt{0.15*0.85}}{0.04}

(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.15*0.85}}{0.04})^{2}

n = 17.5

Rounding up

The sample size needed if the margin of error of the confidence interval is to be about 0.04 is 18.

8 0
3 years ago
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