Step-by-step explanation:
<h3><u>Given :-</u></h3>
[1+(1/Tan²θ)] + [ 1+(1/Cot²θ)]
<h3>
<u>Required To Prove :-</u></h3>
[1+(1/Tan²θ)]+[1+(1/Cot²θ)] = 1/(Sin²θ-Sin⁴θ)
<h3><u>Proof :-</u></h3>
On taking LHS
[1+(1/Tan²θ)] + [ 1+(1/Cot²θ)]
We know that
Tan θ = 1/ Cot θ
and
Cot θ = 1/Tan θ
=> (1+Cot²θ)(1+Tan²θ)
=> (Cosec² θ) (Sec²θ)
Since Cosec²θ - Cot²θ = 1 and
Sec²θ - Tan²θ = 1
=> (1/Sin² θ)(1/Cos² θ)
Since , Cosec θ = 1/Sinθ
and Sec θ = 1/Cosθ
=> 1/(Sin²θ Cos²θ)
We know that Sin²θ+Cos²θ = 1
=> 1/[(Sin²θ)(1-Sin²θ)]
=> 1/(Sin²θ-Sin²θ Sin²θ)
=> 1/(Sin²θ - Sin⁴θ)
=> RHS
=> LHS = RHS
<u>Hence, Proved.</u>
<h3><u>Answer:-</u></h3>
[1+(1/Tan²θ)]+[1+(1/Cot²θ)] = 1/(Sin²θ-Sin⁴θ)
<h3><u>Used formulae:-</u></h3>
→ Tan θ = 1/ Cot θ
→ Cot θ = 1/Tan θ
→ Cosec θ = 1/Sinθ
→ Sec θ = 1/Cosθ
<h3><u>Used Identities :-</u></h3>
→ Cosec²θ - Cot²θ = 1
→ Sec²θ - Tan²θ = 1
→ Sin²θ+Cos²θ = 1
Hope this helps!!
6a. By the convolution theorem,
6b. Similarly,
7. Take the Laplace transform of both sides, noting that the integral is the convolution of 
and 
.
where 
. Then 
, and
We have the partial fraction decomposition,
Then we can easily compute the inverse transform to solve for f(t) :
Answer:
As per dot plots we see the distribution of prices is close but majority of prices are concentrated in different zones. So MAD would be more similar by the look.
<u>Let's verify</u>
<h3>Neighborhood 1</h3>
<u>Data</u>
- 55, 55, 60, 60, 70, 80, 80, 80, 90, 120
<u>Mean</u>
- (55*2+ 60*2+ 70+ 80*3 + 90+ 120)/10 = 75
<u>MAD</u>
- (20*2+15*2+5+5*3+15+45)/10 = 15
<h3>Neighborhood 2</h3>
<u>Data</u>
- 100, 110, 110, 110, 120, 120, 120, 140, 150, 160
<u>Mean</u>
- (100 + 110*3+ 120*3+ 140 + 150+ 160)/10 = 124
<u>MAD</u>
- (24+14*3+4*3+16*3+16+26+36)/10 = 20.4
As we see the means are too different (75 vs 124) than MADs (15 vs 20.4).
Answer:
<em> y = 4.25x</em>
Step-by-step explanation:
Given that:
After 2 week he has used 8 1/2 cups of dog food after 5 week he has used 21 1/4 cups, we can write this in coordinate form (x, y) where;
y is the amount of dog food
x is the time in weeks
The coordinates are (2, 8 1/2) and (5, 21 1/4)
get the slope m:
m = y2-y1/x2-x1
m = (21 1/4 - 8 1/2)/5-2
m = (85/4-17/2)/3
m = (85-34/4)/3
m = 51/12
m = 4.25
Get the intercept c:
Substitute any of the points say (2, 17/2) and m = 51/12 into the equation
y = mx+c
17/2 = 51/12(2) + c
17/2 = 51/6 + c
c = 17/2 - 51/6
c = 51-51/6
c = 0
Get the required equation:
substitute m - 4.25 and c = 0 into y = mx+c
y = 4.25x + 0
<em>Hence the required equation is y = 4.25x</em>
<em></em>
Answer:
The angle of elevation of the sun is 39⁰
Step-by-step explanation:
Given;
height of the tree, h = 96 ft
length of the shadow, L = 120 ft
|
| 96ft
|
|
θ------------------------------------
120ft
Completing this triangle to cut across the top of the tree gives you a right angled triangle with θ as the angle of elevation of the sun.
Apply trig-ratio to determine the angle of elevation of the sun;
tanθ = opposite side / adjacent side
tanθ = 96 / 120
tanθ = 0.8
θ = tan⁻¹(0.8)
θ = 38.7⁰
θ = 39⁰
Therefore, the angle of elevation of the sun is 39⁰
