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marusya05 [52]
3 years ago
15

Solve: – 17 < 2x – 3 < 5 - Give your answer as an interval.

Mathematics
1 answer:
Firdavs [7]3 years ago
5 0
(-7,4) is the awnser
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Need help...........
Kay [80]

<u>The commutative property is when you can change the order and it will be the same answer.</u>

<u>6 + 8 + 7 = 7 + 8 + 6</u> would be your answer.

3 0
3 years ago
Read 2 more answers
What is answer to 12=4x what is x
krek1111 [17]
Division Property of Equality.
Always use opposite operation with side that contains variable.

Isolate variable.
Divide 4 by 4 to get it by itself.

Now do the same to other side.
12\div4=3\\x=3
6 0
3 years ago
Read 2 more answers
The classroom had 35 glue sticks. If the ratio of glue sticks to glue bottles was 5 : 2, how many glue bottles did the classroom
Marat540 [252]

Answer:

14 glue bottles.

Step-by-step explanation:

Let's use a ratio:

sticks : bottles

  5     :     2

  35   :    14

There are 14 glue bottles in the classroom.

7 0
3 years ago
5. Write an expression to represent "Six more than the difference of a number and three."​
ki77a [65]
N-3+6
i dot believe that is the correct answer have an amazing day love ;)
7 0
3 years ago
The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th
inna [77]

Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4   -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

y(y-2)=100

y^2-2y=100

subtracting 100 from both sides

y^2-2y-100=0

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

ax^2+bx+c=0

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

Solving first

y=\frac{2+\sqrt{4+400}{2}

y=\frac{2+\sqrt{404}{2}

y=\frac{2+20.099}{2}

y=\frac{22.099}{2}

y=11.049

Solving second one

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{2-\sqrt{4+400}{2}

y=\frac{2-\sqrt{404}{2}

y=\frac{2-20.099}{2}

y=\frac{-18.99}{2}

y=-9.045

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

4 0
3 years ago
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