Given that ∠B ≅ ∠C.
to prove that the sides AB = AC
This can be done by the method of contradiction.
If possible let AB 
=AC
Then either AB>AC or AB<AC
Case i: If AB>AC, then by triangle axiom, Angle C > angle B.
But since angle C = angle B, we get AB cannot be greater than AC
Case ii: If AB<AC, then by triangle axiom, Angle C < angle B.
But since angle C = angle B, we get AB cannot be less than AC
Conclusion:
Since AB cannot be greater than AC nor less than AC, we have only one possibility. that is AB =AC
Hence if angle B = angle C it follows that
AB = AC, and AB ≅ AC.
Multiply 2.90 by 6 and multiply 2.90 by 4 then add them and you get your answer
Answer:
54,554.5
Step-by-step explanation:
Have you heard about this amazing thing called a calculator?
Answer:
126
Step-by-step explanation:
To calculate this, we need to assume at least one white marble will be picked... so let's take it out of the bag. Then we need to pick 4 more marbles... it's just then a combination calculation.
How many marbles is there in total? 4 + 3 + 2 + 1 = 10
We do just as if we had removed one white marble from the bag... so that leaves 9 in the bag.
We have to pick 4 out of those 9.... so, it's simple combination calculation:
C(9,4) = 9! / (4! (9--4)!) = 9! / (4! 5!) = 126
Some of those grabs will have 2 white marbles... but we're assured that there are 126 ways to combine the 10 marbles so there's at least one white in the 5 picked (since we forced it in our calculations).
