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fredd [130]
3 years ago
15

Brainliest to correct!

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
4 0

szaeAnswer:

fhx

Step-by-step explanation:ees

ffwsc

Ostrovityanka [42]3 years ago
4 0

here u go man the answer is right here

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I need the help on this
Salsk061 [2.6K]

Answer:

Go catipiller

Step-by-step explanation:

8 0
2 years ago
What is 4/7 multiplied by 13/9
nevsk [136]

Answer:

52/63

Step-by-step explanation:

Here, we want to multiply two fractions

we have this as;

4/7 * 13/9

= 52/63

4 0
3 years ago
How many 5-member chess teams can be chosen from 15 interested players? Consider only the members selected, not their board posi
ryzh [129]

<u>Answer</u>:

3003 number of 5-member chess teams can be chosen from 15 interested players.

<u>Step-by-step explanation:</u>

Given:

Number of the interested players =  15

To Find:

Number of 5-member chess teams that can be chosen = ?

Solution:

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations, we will use the formulanCr = \frac{n!}{r!(n - r)!}

where

n represents the total number of items,

r represents the number of items being chosen at a time.

Now  we have n = 15 and r = 5

Substituting the values,

15C_5 = \frac{15!}{5!(15- 5)!}

15C_5 = \frac{15!}{5!(10)!}

15C_5 = \frac{15!}{5!(10)!}

15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{5 \times 4 \times 3 \times 2 \times 1(10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1)}

15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11}{(5 \times 4 \times 3 \times 2 \times 1)}

15C_5 = \frac{360360}{120}

15C_5 = 3003

7 0
3 years ago
How many solutions does the graphed system of equations have:
Alex17521 [72]

Answer:

since the lines don't intersect there is no solution.


8 0
3 years ago
The vertex of a parabola will never be on the axis of symmetry.<br> true or false
Gala2k [10]
False, it's always on the vertex of the parabola.
4 0
3 years ago
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