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Archy [21]
4 years ago
11

The roof of a castle tower is shaped like a cone. The base of the cone is 24 m across and the height is 16 m. The slant height o

f the roof, which is unknown, is the hypotenuse of the right triangle formed with the radius and the height of the cone.
(a) Sketch the roof of the castle tower. Label the known lengths as described and label the unknown length as x.

(b)What is the slant height of the roof?
Mathematics
1 answer:
MaRussiya [10]4 years ago
8 0
<span>my answer for B is 28.84 



hope I could help
</span>
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vovikov84 [41]

Answer:

The answer is the option D

the minimum number of students will be 19

Step-by-step explanation:

Let

x-------> the minimum number of students

we know that

15x\geq 275 ------> inequality that represent the situation

The domain of the inequality is the interval-------> [0,24]

Solve for x

Divide by 15 both sides

x\geq 275/15\\ x\geq 18.33

so

the minimum number of students will be 19

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Using the numbers 3, 5, and 8, can you write nine proper fractions and nine improper fractions? You may use each number only onc
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Answer: 3/5, 3/8, 5/8, 3/58, 3/85, 5/38, 5/83, 8/35, 8/53

8/5, 8/3, 5/3, 85/3, 58/3, 38/5, 35/8, 83/5, 53/8

Step-by-step explanation:

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4 years ago
Please help me find the area of this triangle! I’m not given the height,
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The two legs are 90° apart, so constitute the "base" and "height".
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3 years ago
(a) The plane y + z = 13 intersects the cylinder x2 + y2 = 25 in an ellipse. Find parametric equations for the tangent line to t
klemol [59]

Answer:

Step-by-step explanation:

We have a curve (an ellipse) written as the system of equations

\begin{cases} y+z &= 13\\ x^2+y^2 &= 25\end{cases}.

And we want to calculate the tangent at the point (3,4,9).

The idea in this problem is to consider two variables as functions of the third. Usually we consider y and z as functions of x. Recall that a curve in the space can be written in parametric form in terms of only one variable. In this case we are considering the ‘‘natural’’ parametrization (x, y(x), z(x)).

Recall that the parametric equation of a line has the form

r(t)=\begin{cases} x(t) &= x_0 + v_1t \\ y(t) &= y_0 +v_2t\\ z(t) &= z_0 +v_3t \end{cases},

where (x_0,y_0,z_0) is a point on the line (in this particular case is (3,4,9)) and (v_1,v_2,v_3) is the direction vector of the line. In this case, the direction vector of the line is the tangent vector of the ellipse at the point (3,4,9).

Now, if we have the parametric equation of a curve (x, y(x), z(x)) its tangent line will have direction vector (1, y'(x), z'(x)). So, as we need to calculate the equation of the tangent line at the point (3,4,9) = (3, y(3), z(3)), we must obtain the tangent vector (1, y'(3), z'(3)). This part can be done taking implicit derivatives in the systems that defines the ellipse.

So, let us write the system as

\begin{cases} y(x)+z(x) &= 13\\ x^2+y^2(x) &= 25\end{cases}.

Then, taking implicit derivatives:

\begin{cases} y'(x)+z'(x) &= 0 \\ 2x+2y(x)y'(x) &= 0\end{cases}.

Now we substitute the values x=3 and y(3)=4, and we get the system of linear equations

\begin{cases} y'(3)+z'(3) &= 0 \\ 2\cdot 3+2\cdot 4y'(x) &= 0\end{cases},

where the unknowns are y'(3) and z'(3).

The system is

\begin{cases} y'(3)+z'(3) &= 0 \\ 6+8y'(x) &= 0\end{cases},

and its solutions are

y'(3) = -\frac{3}{4} and z'(3) = \frac{3}{4}.

Then, the direction vector of the tangent is

(1, -\frac{3}{4}, -\frac{3}{4}).

Finally, the tangent line has parametric equation

r(t)=\begin{cases} x(t) &= 3 + t \\ y(t) &= 4 -\frac{3}{4}t\\ z(t) &= 9 +\frac{3}{4}t \end{cases}

where t\in\mathbb{R}.

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We first determine the height that the top of the ladder will reach given that the angle to be made is no greater than 75°. In the right triangle formed, the hypotenuse is 12. The trigonometric function that is derived from the scenario is,
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Thus, the highest point that the ladder will reach should only be approximately equal to 11.59 ft. 
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