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3 years ago

What is 2/3 divided by 3/4

Mathematics

2 answers:

dangina [55]3 years ago

7 0

2/3 divided by 3/4
Flip and multiply the last fraction or in this case the second fraction
2/3 * 4/3
8/9

Eva8 [605]3 years ago

3 0

<h3>Solution:</h3>

$\frac{2}{3} \div \frac{3}{4} \\ = \frac{2}{3} \times \frac{4}{3} \\ = \frac{8}{9} \\$

<h3>Answer:</h3>

$\frac{8}{9}$

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Anyone know this?? it’s finding the sine of a triangle!!

LenKa [72]

Answer:

I'm not sure what you want me to answer from this, so I solved for every variable:

Angle A: 83°

Side b: 6.29

Side c: 5.8

Step-by-step explanation:

-----Angle A:

Since the sum of the interior angles of a triangle ALWAYS equal 180°, we can solve for angle A as follows:

$A+51+46=180\\A+97=180\\A=83$

-----Side b:

Here, we use the sin rule for finding sides, since we know all of the angles as well as one side:

$\frac{a}{sin(A)} =\frac{b}{sin(B)} \\\frac{8}{sin(83)} =\frac{b}{sin(51)} \\8.06=\frac{b}{0.78} \\6.29=b$

-----Side c:

$\frac{a}{sin(A)} =\frac{c}{sin(C)} \\\frac{8}{sin(83)}=\frac{c}{sin(46)} \\8.06=\frac{c}{0.72} \\5.8=c$

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2 years ago

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How is "y more than 4 is -36" written and what is the answer

Crazy boy [7]

Answer:

y+4=-36 and the answer is y=-40

Step-by-step explanation:

So the word is means equals, meaning we can change it to say

"y more than 4 = -36

and more than means addition so we can put a plus sign there and we get

y+4=-36

then to solve this equation we need to get y by itself on one side and to do that we can move the 4 to the other side by subtracting it on both sides to cancel out the addition and we get y=-40

I hope this helps and please don't hesitate to ask if there is anything still unclear!

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3 years ago

I will mark someone brainliest <br><br> The snack that smiles back ____

brilliants [131]

Answer:

goldfish

Step-by-step explanation:

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Find the maximum and minimum values attained by f(x, y, z) = 5xyz on the unit ball x2 + y2 + z2 ≤ 1.

Allushta [10]

Check for critical points within the unit ball by solving for when the first-order partial derivatives vanish:
$f_x=5yz=0\implies y=0\text{ or }z=0$
$f_y=5xz=0\implies x=0\text{ or }z=0$
$f_z=5xy=0\implies x=0\text{ or }y=0$

Taken together, we find that (0, 0, 0) appears to be the only critical point on $f$ within the ball. At this point, we have $f(0,0,0)=0$ .

Now let's use the method of Lagrange multipliers to look for critical points on the boundary. We have the Lagrangian

$L(x,y,z,\lambda)=5xyz+\lambda(x^2+y^2+z^2-1)$

with partial derivatives (set to 0)

$L_x=5yz+2\lambda x=0$
$L_y=5xz+2\lambda y=0$
$L_z=5xy+2\lambda z=0$
$L_\lambda=x^2+y^2+z^2-1=0$

We then observe that

$xL_x+yL_y+zL_z=0\implies15xyz+2\lambda=0\implies\lambda=-\dfrac{15xyz}2$

So, ignoring the critical point we've already found at (0, 0, 0),

$5yz+2\left(-\dfrac{15xyz}2\right)x=0\implies5yz(1-3x^2)=0\implies x=\pm\dfrac1{\sqrt3}$
$5xz+2\left(-\dfrac{15xyz}2\right)y=0\implies5xz(1-3y^2)=0\implies y=\pm\dfrac1{\sqrt3}$
$5xy+2\left(-\dfrac{15xyz}2\right)z=0\implies5xy(1-3z^2)=0\implies z=\pm\dfrac1{\sqrt3}$

So ultimately, we have 9 critical points - 1 at the origin (0, 0, 0), and 8 at the various combinations of $\left(\pm\dfrac1{\sqrt3},\pm\dfrac1{\sqrt3},\pm\dfrac1{\sqrt3}\right)$ , at which points we get a value of either of $\pm\dfrac5{\sqrt3}$ , with the maximum being the positive value and the minimum being the negative one.

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Step-by-step explanation:

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