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Anuta_ua [19.1K]
3 years ago
5

Find the area of the blue sector of the circle. Round to the nearest hundredth.

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
8 0
A diagram must be associated with the question above. Based on what I researched, this is what I got.

The blue sector of the circle is 120 degrees.

area of the blue sector = 1/3  of pi * 2^2
                                     = 4.19cm2

I hope this answer helps.
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As a membership fee a health club charges a one time amount of $40 and charges $25 for each month. The total fee after m months
ICE Princess25 [194]
First you need to set up an equation y = mx + b. m would be the monthly charge and b would be the one time fee. x represents the number of months.
To solve for the number of months with a total price of 240 we substitute 240 in for y and solve for x.
240 = 25x + 40
subtract 40 from each side
200= 25x
divide by 25
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3 0
3 years ago
Please help this is urgent and I am being timed
Shkiper50 [21]
Hi there!

Pauline simplified the expression correctly.

Pauline made sure she used the distributive property and combined like terms after doing so.

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5 0
3 years ago
Find an upper limit for the zeroes 2x^4 -7x^3 + 4x^2 + 7x - 6 = 0
erik [133]

<u>Answer-</u>

2 is the upper limit for the zeros.

<u>Solution-</u>

The given function f(x) is,

2x^4 -7x^3 + 4x^2 + 7x - 6 = 0

For calculating the zeros,

\Rightarrow f(x)=0

\Rightarrow 2x^4 -7x^3 + 4x^2 + 7x - 6 = 0

\Rightarrow 2x^4-4x^3-3x^3+6x^2-2x^2+ 4x+3x-6=0

\Rightarrow 2x^3(x-2)-3x^2(x-2)-2x(x-2)+3(x-2)=0

\Rightarrow (x-2)(2x^3-3x^2-2x+3)=0

\Rightarrow (x-2)(x^2(2x-3)-1(2x-3))=0

\Rightarrow (x-2)(x^2-1)(2x-3)=0

\Rightarrow (x-2)(x+1)(x-1)(2x-3)=0

\Rightarrow x-2=0,\ x+1=0,\ x-1=0,\ 2x-3=0

\Rightarrow x=2,\ x=-1,\ x=1,\ x=\frac{3}{2}

From all the 4 roots, it can be obtained that 2 is the greatest zero.

7 0
3 years ago
108÷9⋅(−12)÷6−(100÷5)
pochemuha

Answer:

-44

Step-by-step explanation:

5 0
3 years ago
Find all Values of b that will make the polynomial a perfect square trinomial.
weeeeeb [17]

Answer:

10,404/334,084

Step-by-step explanation:

Given the polynomial

289r^2 - 102r + c

We are to find the value of c that will make it a perfect square

Divide through by 289

289r²/289 - 102r/289 + c/289

Half of the coefficient of r is 1/2(102/289)

Half of the coefficient of r = 102/578

Square the result

r² = (102/578)²

r² = 10,404/334,084

Hence the required constant is 10,404/334,084

8 0
3 years ago
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