It's actually 70
28 + 28*1.5
I just showed you 5556666666
You have to know a great deal more about where Q and Q' are before you can say much of anything. The problem is listed a s a middle school problem so you are likely permitted to go by the way it looks, but that is not a habit that I would continue using.
So if the triangles SQR and S'Q'R' are congruent, and if they are orientated exactly the same way which means that the distance between QQ' and RR' is a constant (and those are big ifs), then you can claim that QQ' is parallel to the other two lines. Is it the same length as the other two? Again, you obtained the other two by measurement. It looks like SQR and S'Q'R' are equilateral and if that is correct then yes they lengths are all equal. But your marker could do just about anything with this question.
If you have a person marking this, talk it over with them. I say QQ' is equal and parallel to the other two, but don't be surprised if it is wrong.
Answer:
The square below has an area of x^2-10x+25x
2
−10x+25x, squared, minus, 10, x, plus, 25 square meters.
What expression represents the length of one side of the square?
Step-by-step explanation:
Answer:
Step-by-step explanation:
x=64 degrees
y=52 degrees
It is an isosceles triangle which has two angles of the same measurement, Pretty easy to figure out.
