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3 years ago

6

I have an unlimited supply of standard 6-sided dice. What's the fewest number of dice that I have to simultaneously roll to be a

t least 90% likely to roll at least one 6?

1 answer:

lorasvet [3.4K]3 years ago

6 0

You need at least thirteen dice.

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Niko bought 4 stamps each week for 3 weeks. He wants to put 6 stamps on each page of his album. How many pages will niko use?

astraxan [27]

You multiply 4 by 3 because he got 4 stamps each week for 3 weeks. That leads to it being 12 stamps in total.
He wants 6 stamps out of 12 on each page of his album, so you divide 12 by 6 and get two.
He will use 2 pages.
The tools used were mathematical reasoning, multiplication and division.

8 0

3 years ago

Please help me!!!! Solve for x <br> 5^x = 5^3 x 5^8

AnnZ [28]

Answer:

x=11

Step-by-step explanation:

trust i guess

3 0

2 years ago

Read 2 more answers

this is part 2 and you just have to find the total area in sq ft and also answer how much material do you need to make 3 backpac

Lubov Fominskaja [6]

1. 1 1/8= 18/16

5/16*2= 10/16

4/16*2= 8/16

9/16= 9/16

1/2= 8/16

18/16 + 10/16 + 8/16 + 9/16 + 8/16= 53/16

Simplify:

4 & 5/16sq ft

2. All you do is multiply that by 3... so 4 & 5/16 = 53/16 53/16*3 = 159/16 = 9 & 15/16 sq ft

8 0

3 years ago

HELP ME I NEED HELP!!!!

eduard

Answer:

D

Step-by-step explanation:

Since they are the same variables

7 0

3 years ago

a storeroom 21 feet long, 15 feet wide, and 11 feet high was enlarged to a length of 25 feet and a width of 17 feet. how many cu

xenn [34]

<h2>1210 cubic feet</h2>

Step-by-step explanation:

Initial dimensions of the storeroom were $21\text{ }ft$ length, $15\text{ }ft$ width and $11\text{ }ft$ height.

The room is in the shape of a cuboid. Volume of a cuboid = $V=l\times b\times h$ , where $l,b,h$ are the length, width and height of the cuboid.

So, Volume of storeroom initially = $21\text{ }ft\text{ }\times15\text{ }ft\text{ }\times11\text{ }ft\text{ }=3465\text{ }ft^{3}\text{ }$

Finally, the length was increased to $25\text{ }ft$ and width to $17\text{ }ft$ .

Final volume of storeroom = $25\text{ }ft\text{ }\times 17\text{ }ft\text{ }\times 11\text{ }ft\text{ }=4675\text{ }ft^{3}\text{ }$

Increase in volume = $4675\text{ ft}^{3}-3465\text{ ft}^{3}=1210\text{ ft}^{3}$

∴ 1210 cubic feet of storage was added.

7 0

3 years ago