If you are using Microsoft Excel, then that would be easy.
In a spreadsheet, there are rows and columns. Click the row or cell adjacent to the new column that you will be adding. In versions of MS Excel 2007 and up, here's what you are going to do. In Home Tab, you can find "Insert" button. Click "Insert", then select "Insert Sheet Columns."
Answer:
Entities are - Students, CourseList, Advisor and CourseSelection.
Explanation:
The database is structure is designed using Crow Foot Database Notation as attached
There are different kinds of installations of system software. If you wish to install a new OS, the type of boot setup that one should create a dual.
A dual boot, or multiboot when used, allows one to be able to install a new OS without hindering the activity of the old one, so that one can boot to either OS.
Multi-booting is simply known as the process whereby a person installs multiple operating systems on a single computer, and being able to choose which one to boot.
Dual-booting is a very common configuration that is known to all. It pertains to two operating systems.
See full question below
If you wish to install a new OS without disturbing the old one so that you can boot to either OS, what type of boot setup should you create?
dual
cross
controlled
Learn more about dual boot from
brainly.com/question/13483046
Answer:
To check if the year comes under each 100th year, lets check if the remainder when dividing with 100 is 0 or not.
Similarly check for 400th year and multiple 0f 4. The following C program describes the function.
#include<stdio.h>
#include<stdbool.h>
bool is_leap_year(int year);
void main()
{
int y;
bool b;
printf("Enter the year in yyyy format: e.g. 1999 \n");
scanf("%d", &y); // taking the input year in yyyy format.
b= is_leap_year(y); //calling the function and returning the output to b
if(b==true)
{
printf("Thae given year is a leap year \n");
}
else
{
printf("The given year is not a leap year \n");
}
}
bool is_leap_year(int year)
{
if(year%100==0) //every 100th year
{
if(year%400==0) //every 400th year
{
return true;
}
else
{
return false;
}
}
if(year%4==0) //is a multiple of 4
{
return true;
}
else
{
return false;
}
}
Explanation:
Output is given as image
The answer is C. Jurassic.