Be persuasive, have form, and know what you are talking about. I would recommend using MELCON. You can learn more about MELCON with this link. http://melcon.weebly.com/
Answer:
!(key == 'q')
Explanation:
Based on the description, the coded expression that would equate to this would be
!(key == 'q')
This piece of code basically states that "if key pressed is not equal to q", this is because the ! symbol represents "not" in programming. Meaning that whatever value the comparison outputs, it is swapped for the opposite. In this case, the user would press anything other than 'q' to continue, this would make the expression output False, but the ! operator makes it output True instead.
Answer:
num = float(input("Enter a number : "))
ab = abs(num)
sqrt = float(ab ** 0.5)
print(sqrt)
Explanation:
I am not sure what the 'following's are
but it should result the sum of all cells between and including C5 and C18.
Answer:
#include <stdio.h>
int hexToDec(const int hexNum[]){
int result = 0, prod = 1;
for(int i = 3;i>=0;i-=1){
result += (prod*hexNum[i]);
prod = prod * 16;
}
return result;
}
int main()
{
int hexNum[4], i;
char s[5], ch;
printf("Enter hexa decimal value: ");
scanf("%s",s);
for(i = 0;i<4;i++){
ch = s[i];
if(ch>='0' && ch<='9'){
hexNum[i] = ch-'0';
}
else if((ch>='a' && ch<='f') || (ch>='A' && ch<='F')){
if(ch=='A' || ch=='a'){
hexNum[i] = 10;
}
else if(ch=='B' || ch=='b'){
hexNum[i] = 11;
}
else if(ch=='C' || ch=='c'){
hexNum[i] = 12;
}
else if(ch=='D' || ch=='d'){
hexNum[i] = 13;
}
else if(ch=='E' || ch=='e'){
hexNum[i] = 14;
}
else{
hexNum[i] = 15;
}
}
}
printf("%d",hexToDec(hexNum));
return 0;
}
Explanation:
