A garden has a perimeter of 160 feet. The length is 12 more than the width. Find the length width of the garden.

Mathematics

1 answer:

andrey2020 [161]1 year ago

8 0

we have the following:

$\begin{gathered} p=2\cdot l+2\cdot w \\ l=w+12 \\ p=160 \end{gathered}$

replacing:

$\begin{gathered} p=2\cdot(w+12)+2\cdot w \\ 160=2\cdot w+24+2\cdot w \\ 4\cdot w=160-24 \\ w=\frac{136}{4} \\ w=34 \end{gathered}$

therefore, the width is 34 feet, the length:

$\begin{gathered} l=34+12 \\ l=46 \\ \end{gathered}$

the length is 46 feet

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Ms walkers science class is doing an egg drop experiment from the balcony of their school. Each egg is protected by a contraptio

mr_godi [17]

Answer:

The zeros, -1.48 and 1.48, represent the times where the egg is on the ground.

Step-by-step explanation:

The roots, or zeros, of an expression are the x-intercepts. They are the points where the data crosses the x-axis. The y-coordinate at these points is 0. This means the height of the egg at these points is 0.

The values of a, b and c in this equation are -16, 0 and 35. Using the quadratic formula,

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\=\frac{-0\pm \sqrt{0^2-4(-16)(35)}}{2(-16)}\\\\=\frac{0\pm \sqrt{0--2240}}{-32}\\\\=\frac{0\pm \sqrt{2240}}{-32}\\\\=\frac{0\pm 47.33}{-32}\\\\=\frac{0+47.33}{-32}\text{ or }\frac{0-47.33}{-32}\\\\=\frac{47.33}{-32}\text{ or }\frac{-47.33}{32}\\\\=-1.48\text{ or }1.48$