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oksian1 [2.3K]
3 years ago
13

Evaluate 2y²(x+y) when x = 1 and y = 5 Show working out

Mathematics
2 answers:
Svetlanka [38]3 years ago
5 0

Answer:

300

Step-by-step explanation:

2y²(x+y)

2(5)²(1+5)

2(25)6

(50)6

300

Please mark as brainliest.

Harlamova29_29 [7]3 years ago
4 0

Answer:

300

Step-by-step explanation:

2(5)²(1+5)

2(25)(6)

50(6)

300

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disa [49]
7.6375 =

1 Decimal Place = 7.6
<span>2 Decimal Place = 7.64
</span><span>3 Decimal Place = 7.638
</span><span>4 Decimal Place = 7.6375
</span>
So the answer is 7.64   .
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Alenkasestr [34]

Answer:

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Step-by-step explanation:

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<em>Additional</em><em> </em><em>information</em><em>:</em>

<em>Prime</em><em> </em><em>numbers</em><em> </em><em>are</em><em> </em><em>those</em><em> </em><em>numbers</em><em> </em><em>which</em><em> </em><em>can</em><em> </em><em>only</em><em> </em><em>be</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>itself</em><em> </em><em>.</em><em>for</em><em> </em><em>instance</em><em>:</em><em>1</em><em>,</em><em>2</em><em>,</em><em>3</em><em>,</em><em>5</em><em>,</em><em>7</em><em> </em><em>,</em><em>1</em><em>1</em><em>,</em><em>1</em><em>3</em><em> </em><em>etc</em><em>.</em>

<em>Composite</em><em> </em><em>number</em><em> </em><em>s</em><em> </em><em>are</em><em> </em><em>those</em><em> </em><em>numbers</em><em> </em><em>which</em><em> </em><em>can</em><em> </em><em>be</em><em> </em><em>also</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>other</em><em> </em><em>numbers</em><em>,</em><em>For</em><em> </em><em>instance</em><em>:</em><em> </em><em>4</em><em>,</em><em>6</em><em>,</em><em>8</em><em>,</em><em>1</em><em>0</em><em> </em><em>etc</em>

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