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ratelena [41]
2 years ago
15

Omg please help which shows all solutions of (x+3)^2=12

Mathematics
1 answer:
Leokris [45]2 years ago
7 0

Answer:

So there is an exact form and decimal form,

Step-by-step explanation:

Exact form

x=2 root 3-3, -2 root 3-3

or

x=2\sqrt{3} -3, -2 \sqrt{3} -3

decimal form

x= 0.46410161

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5 and negative 5

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The absolute value is the distance from 0 five and negative 5 are both the same distance from zero

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If the radius of a circle with a area of 5.3 mm squared is multiplied by 5,
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Fifty-three percent of employees make judgements about their co-workers based on the cleanliness of their desk. You randomly sel
GarryVolchara [31]

Answer:

The unusual X values ​​for this model are: X = 0, 1, 2, 7, 8

Step-by-step explanation:

A binomial random variable X represents the number of successes obtained in a repetition of n Bernoulli-type trials with probability of success p. In this particular case, n = 8, and p = 0.53, therefore, the model is {8 \choose x} (0.53) ^ {x} (0.47)^{(8-x)}. So, you have:

P (X = 0) = {8 \choose 0} (0.53) ^ {0} (0.47) ^ {8} = 0.0024

P (X = 1) = {8 \choose 1} (0.53) ^ {1} (0.47) ^ {7} = 0.0215

P (X = 2) = {8 \choose 2} (0.53)^2 (0.47)^6 = 0.0848

P (X = 3) = {8 \choose 3} (0.53) ^ {3} (0.47)^5 = 0.1912

P (X = 4) = {8 \choose 4} (0.53) ^ {4} (0.47)^4} = 0.2695

P (X = 5) = {8 \choose 5} (0.53) ^ {5} (0.47)^3 = 0.2431

P (X = 6) = {8 \choose 6} (0.53) ^ {6} (0.47)^2 = 0.1371

P (X = 7) = {8 \choose 7} (0.53) ^ {7} (0.47)^ {1} = 0.0442

P (X = 8) = {8 \choose 8} (0.53)^{8} (0.47)^{0} = 0.0062

The unusual X values ​​for this model are: X = 0, 1, 7, 8

6 0
3 years ago
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Carla had a piece of rope that was 14 7/8 inches long. She used some of the rope for a crafts project. Now there is 14 3/8 in. L
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Answer:

4/8, 1/2

Step-by-step explanation:

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6 0
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