Answer:
Option a)
Step-by-step explanation:
To get the vertical asymptotes of the function f(x) you must find the limit when x tends k of f(x). If this limit tends to infinity then x = k is a vertical asymptote of the function.

Then. x = 2 it's a vertical asintota.
To obtain the horizontal asymptote of the function take the following limit:

if
then y = b is horizontal asymptote
Then:

Therefore y = 0 is a horizontal asymptote of f(x).
Then the correct answer is the option a) x = 2, y = 0
Answer:
11
Step-by-step explanation:
Hope it helps you :)
Can I see the picture it’s blurry
Answer:
The answer is It is between 0 and 1
Step-by-step explanation:
If you solve the problem step by step as (-2^3)^-2<1 then it comes out as true so it would be less than 1 but more then 0.
10 degrees is in a 90 degree angle
90-10 =80
use sin
sin(80)=9/x
get x alone
x=9/sin(80)