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olasank [31]
2 years ago
6

Hjjhhhhhhjjjjjjjjhjjhhhhh hhhhhj h​

Mathematics
2 answers:
storchak [24]2 years ago
7 0

Answer:

dnbdjdndh hdhdhbdjf

xnxnxnnxnxnfnf

ndndndndjf

elena-s [515]2 years ago
4 0

Answer:

YASSSSSSSS

Step-by-step explanation:

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Simplify (2/5÷3/8)÷(-3/5)
liberstina [14]

Answer:

\pink{ - 1 \frac{7}{9} }

Step-by-step explanation:

( \frac{2}{5}  \div  \frac{3}{8} ) \div ( -  \frac{3}{5} ) \\ (\frac{2}{5}  \times  \frac{8}{3} ) \times ( -  \frac{5}{3} ) \\  \frac{16}{15}  \times  -  \frac{5}{3}  \\ -   \frac{80}{45}

As the answer can be more simplified, divide both numerator and denominator by 5.

-  \frac{16}{9}  =   - 1 \frac{7}{9}

3 0
1 year ago
Use the scale of 1 cm:15 cm to find each missing dimension.
Hunter-Best [27]

Answer:

1 the answer is 60

2. the answer is 135

3. the answer is 337.5

4 0
3 years ago
Read 2 more answers
Which statement is true about the line represented on the equation y + 7 = -3 (x - 2/9) ?
Zarrin [17]

<u>ANSWER</u>

The point (\frac{2}{9},-7) lies on the straight line y+7=-3(x-\frac{2}{9})

<u>EXPLANATION</u>

The given line is y+7=-3(x-\frac{2}{9}). It can be observed that the given straight line is in the point-slope form.

We can rewrite the equation in the point-slope form to obtain,


y--7=-3(x-\frac{2}{9}).


When we compare this to the general point-slope form, which given by the formula;

y-y_1=m(x-x_1),

We can observe that,

x_1=\frac{2}{9} and y_1=-7.


Hence the point, (x_1,y_1)=(\frac{2}{9},-7) lies on y+7=-3(x-\frac{2}{9})

6 0
3 years ago
In the Present Value of an Ordinary Annuity formula, what does the n represent?
WITCHER [35]
The answer is D. decimal number of percentage
5 0
3 years ago
A school had 225 students enrolled last year. This year, 260 students are enrolled. Find the percent of change to the
Katarina [22]

Answer:

15.5%

Step-by-step explanation:

No of students that had enrolled last year = 225

This year, 260 students are enrolled.

We need to find the percent of change in the number of students. It can be calculated as :

P = (change in no of students/initial no of students)×100

\%=\dfrac{260-225}{225}\times 100\\\\=15.5\%

So, the percent change is 15.5%.

8 0
3 years ago
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