3. The figure below is a composite shape that consists of a semicircle and an equilateral triangle (triangle

Mathematics

1 answer:

Ivenika [448]3 years ago

8 0

Answer:

See explanation below

Step-by-step explanation:

Area = Area of triangle + Area of the semi circle

Area of triangle = 1/2bh

Area of triangle = 1/2 *(5/2)(4)

Area of triangle = 1/2(2.5)*4

Area of triangle = 2 * 2.5

Area of triangle = 5cm^2

Area of semicircle = πr²/2

r = 2.5cm

Area of semicircle =(3.14)(2.5)²/2

Area of semicircle = = 3.14 * 4.5

Area of semicircle = 9.8125cm^2

Area pf the figure = 5+9.8125

Area pf the figure = 14.8125cm^2

For the perimeter

Perimeter of the semicircle = 2πr

Perimeter of the semicircle = 2(3.14)(2.5)

Perimeter of the semicircle = 15.7cm

Perimeter of the semicircle = = 15.7 + 5 + 5

Perimeter of the semicircle = 25.7cm

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tatuchka [14]

Answer:

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Step-by-step explanation:

6 0

3 years ago

Given that f(x)= x2+3 and g(x)= x+4/3 solve for (f(g(x)) when x =2

Savatey [412]

$\bf \begin{cases}
f(x)=x^2+3\\\\
g(x)=x+\cfrac{4}{3}
\end{cases}
\\\\\\
\boxed{x=2}\qquad g(2)=(2)+\cfrac{4}{3}\implies \boxed{g(2)=\cfrac{10}{3}}
\\\\\\
f(~~g(x)~~)=[g(x)]^2+3\implies f(~~g(2)~~)=[g(2)]^2+3
\\\\\\
f(~~g(2)~~)=\left[ \boxed{\frac{10}{3}} \right]^2+3\implies f(~~g(2)~~)=\cfrac{10^2}{3^2}+3
\\\\\\
f(~~g(2)~~)=\cfrac{100}{9}+3\implies f(~~g(2)~~)=\cfrac{100+27}{9}
\\\\\\
f(~~g(2)~~)=\cfrac{127}{9}$