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2 years ago

The radius is longer than a chord that doesn't pass through the centre.

Mathematics

1 answer:

BigorU [14]2 years ago

3 0

Step-by-step explanation:

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CBSE

Mathematics

Grade 10

Circles

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Round to the tenths place .712 .665 .545

Artyom0805 [142]

.712 rounds to .7

.665 rounds to .7

.545 rounds to .5

5 0

3 years ago

Learning Task 3: In your answer sheet, write the letter of the correct answe

miss Akunina [59]

Answer:

a.) May or may not a polynomial function ( depends on c)

b.) Not a polynomial function.

c.) Not a polynomial function.

d.) It is a polynomial function.

Step-by-step explanation:

A polynomial function is of the form - $a_{n}x^{n} + a_{n-1} x^{n-1} + a_{n-2} x^{n-2} + .....+ a_{1}x + a_{0}$

where n is positive integer and n $\neq$ 0

a.)

P(x) = 2x³ + 32 - 4x + 4c

It may or may not a polynomial function because we did not know about the constant c.

b.)

H(x) = 4 $x^{\frac{1}{2} }$ - 3x⁴

It is not a polynomial function because $\frac{1}{2}$ is not integer.

c.)

G(x) = 2 $x^{-3}$ + 5

It is not a polynomial function because -5 is not a positive integer.

d.)

F(x) = 2x³ - 5x + 33x²

It is a polynomial function.

8 0

2 years ago

Which expression is equivalent to (4p^-4 q)^-2/ 10pq^-3?

Anit [1.1K]

Answer:

$\dfrac{p^{7} q}{160}$

Step-by-step explanation:

$\dfrac{(4p^-4 q)^-2}{10pq^-3} =$

$= \dfrac{4^{-2}p^{-4\times (-2)} q^{-2}}{10pq^-3}$

$= \dfrac{4^{-2}}{10}p^{8-1} q^{-2-(-3)}$

$= \dfrac{1}{4^2 \times 10}p^{7} q^{-2 + 3}$

$= \dfrac{1}{160}p^{7} q$

$= \dfrac{p^{7} q}{160}$

4 0

2 years ago

Read 2 more answers

Prove algebraically that 0.5 recurring = 5/9

weeeeeb [17]

Answer:

see explanation

Step-by-step explanation:

We require 2 equations with the recurring part after the decimal point.

Let x = 0.555..... → (1)

Multiply both sides by 10, then

10x = 5.555..... → (2)

Subtract (1) from (2) thus eliminating the recurring decimal

(10x - x) = (5.5555 - 0.5555 ), that is

9x = 5 ( divide both sides by 9 )

x = $\frac{5}{9}$

5 0

2 years ago

Find the Area of the figure below, composed of a rectangle and a semicircle. Round to the nearest tenth place.

kap26 [50]

Answer: 68.1

Step-by-step explanation:

The area of a semi-circle is 1/2 the area of a full circle. The area of a full circle is pi*r^2. Therefore, the area of a semi-circle is:

$Area=\pi r^2/2$

$Area=\pi (3)^2/2=9\pi /2$

The area of a rectangle is the length multiplied by the width:

$Area=l*w$

$Area=6*9=54$

The net area is the sum of the rectangle and the semi-circle:

$Area=(9\pi /2)+(54)=68.1$

8 0

2 years ago