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3 years ago

7

Solve for c C^2-25-11

1 answer:

olya-2409 [2.1K]3 years ago

4 0

C3-36

the 3 is “c3” is an exponent btw!

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a shipement of 14 microwave ovens contains six defective units A vending company has ordered 4 of these units and selection will

kupik [55]

Answer:

The probability that all 4 units are good is 10.66%.

Step-by-step explanation:

Given that a shipement of 14 microwave ovens contains six defective units, and a vending company has ordered 4 of these units and selection will be random, to determine what is the probability that all 4 units are good the following calculation must be performed:

14 - 6 = 8

8/14 x 8/14 x 8/14 x 8/14 = X

0.5714 x 0.5714 x 0.5714 x 0.5714 = X

0.1066 = X

0.1066 x 100 = 10.66

Therefore, the probability that all 4 units are good is 10.66%.

3 0

2 years ago

A ___ equation is a second-degree equation of the form ax^2+bx+c=0 where a ≠ 0

klasskru [66]

Answer:

A quadratic equation is second degree equation with the standard form ax^2+bx+c=0 as the highest power is 2.

__________________.

6 0

2 years ago

Can someone please help me?

VikaD [51]

Answer:

The answer is 27

Step-by-step explanation:

The reason being, you can solve this 2 ways.

1) Combine like terms, 7a-4a = 3a.

Now just substitute (a=9) into 3a.

3 * (9) = 27.

2) Or just substitute a = 9 into the original expression.

7 * (9) - 4 * (9)

= 63 - 36 = 27

4 0

3 years ago

Read 2 more answers

A study of peach trees found that the average number of peaches per tree was 725. The standard deviation of the population is 70

TEA [102]

Answer:

She needs to sample 189 trees.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.025 = 0.975$ , so Z = 1.96.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

The standard deviation of the population is 70 peaches per tree.

This means that $\sigma = 70$

How many trees does she need to sample to obtain an average accurate to within 10 peaches per tree?

She needs to sample n trees.

n is found when M = 10. So

$M = z\frac{\sigma}{\sqrt{n}}$

$10 = 1.96\frac{70}{\sqrt{n}}$

$10\sqrt{n} = 1.96*70$

Dividing both sides by 10:

$\sqrt{n} = 1.96*7$

$(\sqrt{n})^2 = (1.96*7)^2$

$n = 188.2$

Rounding up:

She needs to sample 189 trees.

3 0

3 years ago

saul85 [17]

Answer:

The ans from the bottom left

8 0

3 years ago