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Lyrx [107]
3 years ago
7

Solve for c C^2-25-11

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
4 0
C3-36

the 3 is “c3” is an exponent btw!
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If 50 grams of sweets cost 250 rupees find the cost of 380 grams of sweets. ​
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Which expression is equivalent to (x superscript four-thirds baseline x superscript two-thirds Baseline ) superscript one-third
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<h3><u>The equivalent expression is:</u></h3>

(x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = x^{\frac{2}{3}

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

\displaystyle (x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}}

We have to find the equivalent expression

We can simplify the above expression using law of exponents

<em><u>Use the following law of exponents:</u></em>

a^m \times a^n = a^{m+n}

Therefore,

\displaystyle (x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = (x^{\frac{4}{3}+\frac{2}{3}})^{\frac{1}{3}}\\\\Simplify\\\\\displaystyle (x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = (x^2)^\frac{1}{3}

<em><u>Use another law of exponent</u></em>

(a^m)^n = a^{mn}

Therefore,

(x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = x^{\frac{2}{3}

Thus the equivalent expression is found

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