3 years ago

Solve for c C^2-25-11

Mathematics

1 answer:

olya-2409 [2.1K]3 years ago

4 0

C3-36

the 3 is “c3” is an exponent btw!

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Make v the subject of the formula

EleoNora [17]

$T =\dfrac 5{V+1}\\\\\\\implies VT+T = 5\\\\\implies VT = 5-T\\\\\implies V =\dfrac{5-T}T$

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3 years ago

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What is the solution to the system of equations? Use the substitution method.

BabaBlast [244]

The answer is:
4x+2y=11} 4x+2y=11} x=2-2y
x-2=-2y } x+2y=2 } x=2-2(-3/6)
x=2-(-6/6)
4(2-2y)+2y=11 x=2-(-1)
8-8y+2y=11 x=3
8-6y=11
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So for my opinion the solution is A.(3,-1/2)

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GarryVolchara [31]

144 I’m not sure tho

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Giving brainless to anyone you can answer the question CORRECT. I’ll also give more points on a next question if you answer it r

navik [9.2K]

Answer:

1. 104

2. 52

3. 52

Step-by-step explanation:

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3 years ago

The sector of a circle shown to the left has its center at point OO. The arc XYZXYZ has length 10.810.8, and the central angle X

BARSIC [14]

Answer: Length of the radius of the sector is 6 units.

Step-by-step explanation:

Since we have given that

Length of an arc = 10.8

Radian of a central angle = 1.8

First we convert radian into degrees,

$1\ radian= 57.295779513\textdegree\\\\1.8\ radians=1.8\times 57.3\textdegree\\\\1.8\ radians=103.14\textdegree$

As we know the formula for "Length of an arc":

$\text{Length of an arc}=\frac{\theta}{360\textdegree}\times 2\pi r\\\\10.8=\frac{103.14}{360\textdegree}\times 2\times \frac{22}{7}\times r\\\\10.8=1.8r\\\\r=\frac{10.8}{1.8}\\\\r=6$

Hence, Length of the radius of the sector is 6 units.

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3 years ago