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Lyrx [107]
3 years ago
7

Solve for c C^2-25-11

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
4 0
C3-36

the 3 is “c3” is an exponent btw!
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a shipement of 14 microwave ovens contains six defective units A vending company has ordered 4 of these units and selection will
kupik [55]

Answer:

The probability that all 4 units are good is 10.66%.

Step-by-step explanation:

Given that a shipement of 14 microwave ovens contains six defective units, and a vending company has ordered 4 of these units and selection will be random, to determine what is the probability that all 4 units are good the following calculation must be performed:

14 - 6 = 8

8/14 x 8/14 x 8/14 x 8/14 = X

0.5714 x 0.5714 x 0.5714 x 0.5714 = X

0.1066 = X

0.1066 x 100 = 10.66

Therefore, the probability that all 4 units are good is 10.66%.

3 0
2 years ago
A ___ equation is a second-degree equation of the form ax^2+bx+c=0 where a ≠ 0​
klasskru [66]

Answer:

A quadratic equation is second degree equation with the standard form ax^2+bx+c=0 as the highest power is 2.

__________________.

6 0
2 years ago
Can someone please help me?
VikaD [51]

Answer:

The answer is 27

Step-by-step explanation:

The reason being, you can solve this 2 ways.

1) Combine like terms, 7a-4a = 3a.

Now just substitute (a=9) into 3a.

3 * (9) = 27.

2) Or just substitute a = 9 into the original expression.

7 * (9) - 4 * (9)

= 63 - 36 = 27

4 0
3 years ago
Read 2 more answers
A study of peach trees found that the average number of peaches per tree was 725. The standard deviation of the population is 70
TEA [102]

Answer:

She needs to sample 189 trees.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

The standard deviation of the population is 70 peaches per tree.

This means that \sigma = 70

How many trees does she need to sample to obtain an average accurate to within 10 peaches per tree?

She needs to sample n trees.

n is found when M = 10. So

M = z\frac{\sigma}{\sqrt{n}}

10 = 1.96\frac{70}{\sqrt{n}}

10\sqrt{n} = 1.96*70

Dividing both sides by 10:

\sqrt{n} = 1.96*7

(\sqrt{n})^2 = (1.96*7)^2

n = 188.2

Rounding up:

She needs to sample 189 trees.

3 0
3 years ago
1
saul85 [17]

Answer:

The ans from the bottom left

8 0
3 years ago
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