Ratios and Rates word problems

Mathematics

2 answers:

Dafna1 [17]3 years ago

6 0

Answer:

900 people

Step-by-step explanation:

One hour is 60 minutes, and the number of thirty minutes in an hour is two. To get the number of thirty minutes in 6 hours, you would do 2 x 6, which is 12. After this, you would do 12 x 75 since 75 people ride it in 30 minutes. This equals 900.

I hope it helped!

natima [27]3 years ago

4 0

Answer: The ferris wheel could accomodate 900 people in 6 hours. The rate per hour was 150 people.

Step-by-step explanation:

To start off we can find the number of people by deciding how many time slots of 30 minutes are in 6 hours. Since 30 minutes is half an hour we just do 2 times 6 which would give us 12. Since 75 people can fit in 30 minutes then we do 12 times 75 for the whole 6 hours which comes out to 900.

Once we have the number of people in 6 hours then we can find the hourly rate. To do this we just take the number of people (900) in the whole time (6 hours) and divide 6 from 900 which would give us the hourly rate of 150.

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True or False

Hitman42 [59]

Answer:

True

Step-by-step explanation:

To find the average of anything, you add their values together, and then divide that number by how many of them you added.

Here, you are trying to calculate monthly expenditure, so you add their values together (the sum of monthly expenditures) and then you divide it by how many months you used to add up to the sum (divided by the number of months).

Hope this helped ya! :)

4 0

3 years ago

Suppose a punter kicks a football so that the upward component of its velocity is 80 feet per second. If the ball is 3 feet off

Alexxandr [17]

So hmm check the picture below

$\bf \qquad \textit{initial velocity}\\\\ h = -16t^2+v_ot+h_o \qquad \text{in feet}\\
\\
v_o=\textit{initial velocity of the object}\\
h_o=\textit{initial height of the object}\\
h=\textit{height of the object at "t" seconds}\\\\
-----------------------------\\\\
h(t)=3+80t-16t^2\iff h(t)=-16t^2+80t+3$

a)

well, clearly is 80 ft/s

b)

when t = 1? well 80(1)

c)

in the picture, x-axis is the time and y-axis is the height
so, it reaches its maximum at the vertex, after "x" seconds

$\bf \begin{array}{lcccll}
h(t)=&-16t^2&+80t&+3\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)$

so it reached the vertex after $\bf -\cfrac{{{ b}}}{2{{ a}}}\quad seconds$

d)

the maximum height of the ball is $\bf {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\quad feet$