Answer:
Step-by-step explanation:
5x+3y=1
4x-5y=4
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4(5x+3y)=4(1)
-5(4x-5y)=-5(4)
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20x+12y=4
-20x+25y=-20
----------------------
37y=-16
y=-16/37
5x+3(-16/37)=1
5x-48/37=1
5x=1+48/37
5x=37/37+48/37
5x=85/37
x=(85/37)/5
x=(85/37)(1/5)
x=85/185
x=17/37
Answer: x=17/37, y=-16/37. (17/37, -16/37)
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5x+3y=1
8x-10y=4
-----------------
8(5x+3y)=8(1)
-5(8x-10y)=-5(4)
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40x+24y=8
-40x+50y=-20
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75y=-12
y=-12/75=-4/25
5x+3(-4/25)=1
5x-12/25=1
5x=1+12/25
5x=25/25+12/25
5x=37/25
x=(37/25)/5
x=(37/25)(1/5)
x=37/125
Answer: x=37/125, y=-4/25. (37/125, -4/25).
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5x+3y=1
9x-2y=5
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2(5x+3y)=2(1)
3(9x-2y)=3(5)
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10x+6y=2
27x-6y=15
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37x=17
x=17/37
5(17/37)+3y=1
85/37+3y=1
3y=1-85/37
3y=37/37-85/37
3y=-48/37
y=(-48/37)/3
y=(-48/37)(1/3)
y=-48/111
Answer: x=17/37, y=-48/111. (17/37, -48/111).
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The volume is 810 ft^3= 9*10 *x
810=90x
x=810/90
x=9 feet is the long
Answer:

Step-by-step explanation:
The probability of
can be read as the probability of event B occurring given event A. In this question, event A occurs when the chosen player is a girl. There are 7 girls on the soccer team. Event B occurs when the chose player plays defense. Since
stipulates that event A already occurred, we want the probability of choosing a player who prefers defense from the 7 girls. There are 2 girls who prefer defense, hence
.
<u>Alternative:</u>
For dependent events
and
, the conditional probability of event B occurring given A is given by:

indicates the intersection of
and
. In this case, it is the probability that both events occur. Since there are 16 kids on the soccer team and only 2 are girls and prefer defense,
. The probability of event A occurring (chosen player is a girl) is equal to the number of girls (7) divided by the number of kids on the team (16), hence
.
Therefore, the probability of event B occurring, given event A occurred, is equal to:

He earns 10 $ per hours
so u just need to find how many hours did he worked.
1 3/4+3 2/3+2 5/6
71/12 hrs
now multiply it by 10
59.166$