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sveta [45]
3 years ago
8

Please help

Chemistry
1 answer:
Vika [28.1K]3 years ago
8 0

Answer:

1 atom of carbon on the reactant side (CH₄ is methane, 1 carbon, 4 hydrogen).

1 atom of carbon on product side (Law of Conservation of energy proves this).

4 hydrogen on reactant side (CH₄ is methane, 1 carbon, 4 hydrogen).

4 hydrogen on product side (Again, the Law of Conservation of energy proves this)

4 oxygen atom on the reactant side (2O₂ means two diatomic molecules, or two oxygen molecules of 2 atoms each).

4 oxygen atoms on the product side (Law of Conservation of energy).

2 molecules of oxygen on the reactant side.

2 molecules of water on the product side

Yes, the chemical equation is balanced. The amount of atoms is the constant on both the reactant and product side.

A Ionic bond is chemical bond between two oppositely charged ions because of the transfer of valence electrons between them.

A covalent bond is a chemical bond in which two or more atoms share electrons between them. They can also form polar covalent bond or non-polar covalent bonds (Although that depends on the electronegativities of the atom).

The bond of a carbon dioxide molecule is covalent bond (Polar covalent bond if you've learned that yet)

Potassium Fluoride (KFl) form an ionic bond.

2Al₂O₃ --> 4Al + 3O₂

A reducing agent loses electrons while and oxidizing agent gains electrons.

In an endothermic reaction, the total bond energy in the reactants is greater than the bond energy of products so energy is absorbed by the reaction. (For an endothermic reaction, more energy needs to be absorbed than released).

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Someone please help me with the two I got wrong
LenKa [72]

Answer:

yes

Explanation:

8 0
3 years ago
Read 2 more answers
The concentration of hydroxide ions is greater than the concentration of hydronium ions for acidic solutions.
Katena32 [7]

Answer:

True

Explanation:

It's true because the pH is a measure of how basic or acid a solution is. In an acidic medium, the pH scales goes from 0 to 7. While in a basic medium goes from 7 to 14. The lower the pH value of the most acid the solution is.

1. The expression pH = -log(molar concentration of hydronium) allow to calculate the pH of a solution.

2. On the other hand, the expression pOH = -log(molar concentration of hydroxide) allow to determine the pOH of a solution.

The values of pH and pOH always obey the following expression:

pH + pOH = 14

Thus if for instance the pH becomes smaller the pOH must become bigger in order to fulfill the equation. Which means that the concentration of hydronium ions is greater than the hydroxide concentration.

For example, in an acidic medium:

if pH= 3, pOH= 11

In this case the molar concentration of hydronium is 0,001M. And the molar concentration of hydroxide ions is just 0,00000000001M.

6 0
4 years ago
Read 2 more answers
Assuming equal concentrations and complete dissociation, rank these aqueous solutions by their freezing points. nh4cl cobr3 k2so
Illusion [34]
Answer: CoBr3 < K2SO4 < NH4 Cl

Justification:

1) The depression of the freezing point of a solution is a colligative property, which means that it depends on the number of particles of solute dissolved.

2) The formula for the depression of freezing point is:

ΔTf = i * Kf * m

Where i is the van't Hoof factor which accounts for the dissociation of the solute.

Kf is the freezing molal constant and only depends on the solvent

m is the molality (molal concentration).

3) Since, you are assuming equal concentrations and complete dissociation of the given solutes, the solute with more ions in the molecular formula will result  in the solution with higher depression of the freezing point (lower freezing point).

4) These are the dissociations of the given solutes:

a) NH4 Cl (s) --> NH4(+)(aq) + Cl(-) (aq) => 1 mol --> 2 moles

b) Co Br3 (s) --> Co(3+) (aq) + 3Br(-)(aq) => 1 mol --> 4 moles

c) K2SO4 (s) --> 2K(+) (aq) + SO4 (2-) (aq) => 1 mol --> 3 moles

5) So, the rank of solutions by their freezing points is:

CoBr3 < K2SO4 < NH4 Cl
4 0
3 years ago
Read 2 more answers
the heat of fusion of acetone is 5.7 kJ/mol. Calculate to two significant figures the entropy change when 6.3 mol of acetone mel
shtirl [24]

<u>Answer:</u> The entropy change of the process is 2.0\times 10^2J/K

<u>Explanation:</u>

To calculate the entropy change for different phase at same temperature, we use the equation:

\Delta S=n\times \frac{\Delta H_{f}}{T}

where,  

\Delta S = Entropy change

n = moles of acetone = 6.3 moles

\Delta H_{f} = enthalpy of fusion = 5.7 kJ/mol = 5700 J/mol    (Conversion factor:  1 kJ = 1000 J)

T = temperature of the system = -94.7^oC=[273-94.7]=178.3K

Putting values in above equation, we get:

\Delta S=\frac{6.3mol\times 5700J/mol}{178.3K}\\\\\Delta S=201.4J/K=2.0\times 10^2J/K

Hence, the entropy change of the process is 2.0\times 10^2J/K

4 0
4 years ago
The pH of an acid has nothing to do with the strength of the acid.
Levart [38]

Answer:

false

Explanation:

6 0
3 years ago
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