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3 years ago

PLS HELP ME ON MY FINAL MULTIPLE CHOICE

Chemistry

2 answers:

Vladimir79 [104]3 years ago

8 0

The second one is correct

dexar [7]3 years ago

5 0

Answer:

The force would decrease

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Helium gas collected at a pressure of 0.0045 atm is put into a flexible balloon measuring 350 mL in volume. What volume, in mL,

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Answer: 0.25 atm
Evidence: i looked it up

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3 years ago

I need help with these questions please ASAP!!!!!!!

yawa3891 [41]

Answer:#1A #2T #3D #4A

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4 years ago

Why does random error affects precision?

djyliett [7]

Answer:

Thus, random error primarily affects precision. Typically, random error affects the last significant digit of a measurement. The main reasons for random error are limitations of instruments, environmental factors, and slight variations in procedure.

Explanation:

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3 years ago

A certain liquid X has a normal boiling point of 133.60°C and a boiling point elevation constant Kb= 2.46°C kg mol^-1.Calculate

Afina-wow [57]

Answer:

136.63 °C

Explanation:

ΔTb=Tb solution - Tb pure

Where; Tb pure = 133.60°C

molar mass of solute = 121.14 g/mol

number of moles of solute; 52.2g/121.14 g/mol = 0.431 moles

molality = 0.431 moles/350 * 10^-3 = 1.23 molal

Then;

ΔTb = Kb * m * i

Kb = 2.46°C kg mol^-1

m = 1.23 molal

i = 1

ΔTb = 2.46 * 1.23 * 1

ΔTb = 3.03 °C

Hence;

Tb solution = ΔTb + Tb pure

Tb solution = 3.03 °C + 133.60°C

Tb solution = 136.63 °C

6 0

3 years ago

How many minutes will it take to plate out 2.19 g of chromium metal from a solution of Cr3+Cr3+ using a current of 55.2 amps in

Kamila [148]

Answer : The time it take to plate out will be, 3.69 minutes.

Explanation :

First we have to calculate the moles of Cr.

$\text{Moles of }Cr}=\frac{\text{Mass of Cr}}{\text{Molar mass of Cr}}$

Molar mass of Cr = 51.9 g/mol

$\text{Moles of }Cr}=\frac{2.19g}{51.9g/mol}=0.0423mol$

The cathode half-reaction is,

$Cr^{3+}+3e^-\rightarrow Cr$

From this we conclude that,

The number of electrons (n) in the reaction are 3.

The quantity of charge required for the reduction of 1 mole of $Cr^{3+}$ = $3\times F$

The quantity of charge required for the reduction of 0.0423 mole of $Cr^{3+}$ = $0.0423\times 3\times F=0.1269F=0.1269\times 96500C=12245.85C$

Now we have to calculate the time taken.

We know that,

$q=I\times t$

$t=\frac{q}{I}=\frac{12245.85C}{55.2A}=221.845s=3.69min$

Thus, the time it take to plate out will be, 3.69 minutes.

7 0

3 years ago