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Blababa [14]
3 years ago
15

18) through: (-3,-3), parallel to y = -x + 3​

Mathematics
1 answer:
otez555 [7]3 years ago
6 0

Step-by-step explanation:

y + 3 = - (x + 3)

y + 3 = -x - 3

y = -x - 6

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The image of the point (-1,-8) under a translation is (0, -11). Find the coordinates of the image of the point (-4,-1) under the
Vanyuwa [196]

Answer:

(-3,-4)

Step-by-step explanation:

● (-1,-8) => (0,-11)

Notice that to move from -1 to 0 in the x-axis we should go one unit to the right wich means adding 1.

● -1 + 1 = 0

Notice that to move from -8 to -11 in the y-axis we should go 3 units down wich means substracting 3.

● -8-3 = -11

Let's do the same for the second point.

● (-4,-1) => ?

Add 1 to -4

● -4+1 = -3

We moved 1 unit to the right by adding 1

Substract 3 from -1

● -1-3 = -4

We moved down 3 units by substracting 3

So the image of (-4,-1) is (-3,-4)

4 0
3 years ago
What is an expression that has a value of 35
Brut [27]
60-3=2x5

if thats what u r looking for

6 0
2 years ago
PLEASE ANSWER IN THE NEXT FIVE MINUTES!!! What is the volume of a rectangular prism with a height of 5 meters and a base with ar
cluponka [151]

Answer:

95 m³

Step-by-step explanation:

The volume (V) of a rectangular prism is

V = area of base × height

here area = 19 and h = 5, hence

V = 19 × 5 = 95 m³


3 0
3 years ago
"Find an integer, x, such that 5, 10, and x represent the lengths of the sides of an acute triangle.
Contact [7]
A, b, c - the lengths of the sides of the triangle
and a ≤ b ≤ c
then:
a + b > c and if the triangle is an acute triangle then a² + b² > c².

1^o\\5\leq10\leq x\\\\\left\{\begin{array}{ccc}5+10 \ \textgreater \  x\\5^2+10^2 \ \textgreater \  x^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textless \  15\\ x^2 \ \textless \  125\end{array}\right\to\left\{\begin{array}{ccc}x \ \textless \  15\\ x \ \textless \  \sqrt{125}\approx11.1\end{array}\right\\\\\boxed{x=11}\\\\2^o\\5\leq x\leq10\\\\\left\{\begin{array}{ccc}5+x \ \textgreater \  10\\ 5^2+x^2 \ \textgreater \  10^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \  5\\ x^2 \ \textgreater \  75\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \  5\\ x \ \textgreater \  \sqrt{75}\approx8.7\end{array}\right\\\boxed{x=9}

3^o\\x\leq5\leq10\\\\\left\{\begin{array}{ccc}x +5 \ \textgreater \  10\\ x^2+5^2 \ \textgreater \  10^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x^2 \ \textgreater \ 75\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x \ \textgreater \ \sqrt{75}\approx8.7\end{array}\right\\\boxed{x\in\O}\\\\Answer:\boxed{x=9\ or\ x=11}\to your\ answer:\boxed{\boxed{x=11}}
8 0
3 years ago
Read 2 more answers
Bridget is 5 years older than Angad. Paul is 4 years younger than Angad. If the total of their
Ainat [17]

Answer: Bridge is 21 years old

Step-by-step explanation:

Ok so after reading the question I already know that B (Bridget), A (Angad) and P (Paul) is 49 in the sum of age. I also know that B=A+5 and P=A-4. After that I can assume B=P+5+4. So now after we gather everything, the age of all of them is the same if we delete 5, 4, 4 (From B=P+5+4 and P=A-4). 49-5-4-4=36. So now lets assume they are all 12 (36/3=12). B is 5 years older so lets add 5 to B. B=17, A=12 and P=8. 8+12+17= 37. We now know that but 37 is 12 under 49, so lets add the average 12/3=4 so we add 4 to all of them. B=21 A=16 P=12. 21+16+12=49. So Bridge is 21 years old, Angad is 16 years old and Paul is 12 years old

5 0
3 years ago
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