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3 years ago

From the given information, find the value of x.

Mathematics

2 answers:

igor_vitrenko [27]3 years ago

7 0

Answer:

X=45

Step-by-step explanation:

Lines AC and CD meet at a right angle so you half 90 =45

Zielflug [23.3K]3 years ago

4 0

Answer:

x/24

Step-by-step explanation:

bc we smarttttttt

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A sociologist recorded the estimated life expectancies of women born in Center City. Use the data from women born in 1970 and 20

Veronika [31]

$Y=0.213x-352$ will represent this linear model shown in the data table.

<h3>What will be the linear model for the given data?</h3>

Put the values of the x in the all given equations and then check the value of y if the value of y matches the given values in the option

So if we put the value x=1980 in the $Y=0.213x-352$ then

$Y=0.213(1980)-352$

$Y=69.74$

These values are closest to 70.1 whereas other options do not satisfy the condition.

Thus $Y=0.213x-352$ will represent this linear model shown in the data table.

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The graph of the equation given by y=-cos³θ will be as follows:

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Suppose that the population of the scores of all high school seniors who took the SAT Math (SAT-M) test this year follows a Norm

Vlad1618 [11]

Answer:

Confidence = $1-\alpha=1-0.01=0.99$

And then the confidence level would be given by 99%

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

$X \sim N(\mu, \sigma)$

The distribution for the sample mean is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\bar x =512$ represent the sample mean

$\sigma=100$ represent the population standard deviation

n= 100 sample size selected.

The confidence interval is given by this formula:

$\bar X \pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$ (1)

The marginof error for this case is given by Me=25.76. And we know that the formula for the margin of error is given by:

$Me=z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$

$25.76=z_{\alpha/2} \frac{100}{\sqrt{100}}$

And we can find the critical value $z_{\alpha/2}$ like this:

$z_{\alpha/2}=\frac{25.76(\sqrt{100})}{100}=2.576$

And we know that on the right tail of the z score =2.576 we have $\alpha/2$ of the total area. We can find the area on the right of the z score using this excel code:

"=1-NORM.DIST(2.576,0,1,TRUE)" or using a table of the normal standard distribution, and we got 0.004998= $\alpha/2$ , so then $\alpha=0.00498*2=0.009995 \approx 0.01$ , and then we can find the confidence like this: