Answer:
y = (∛x)/3
Step-by-step explanation:
To undo the multiplication by 27, you multiply by its inverse:
(1/27)y = (1/27)(27x^3)
y/27 = x^3 . . . . . . . . . . . simplify
To undo the cube, you take the cube root:
(∛y)/(∛27) = ∛(x^3)
(∛y)/3 = x
Apparently, you want the inverse function, so you swap the variables:
y = (∛x)/3
_____
You can swap the variables at the beginning or end. It doesn't matter. If you do it at the beginning, you have ...
x = 27y^3
and you're solving for y. You use the same inverse operations that we used above.
The answer is <span>Q=(M−2P)/3
</span>
<span>M = 2P + 3Q
Subtract 2P from both sides:
M - 2P = 2P + 3Q - 2P
M - 2P = 3Q
Divide both sides by 3:
(M - 2P)/3 = 3Q/3
(M - 2P)/3 = Q</span>
To better give a visual, I drew it out instead.
The attachment is the solution.
