1. You have that:
- The<span> lengths of the bases are (6x-1) units and 3 units.
- The midsegment has a length of (5x-3) units.
2. To solve this exercise, you must apply the formula for calculate the length of the midsegment of a trapezoid, which is shown below:
Midsegment=Base1+Base2/2
As you can see, the midsegment is half the sum of the bases of the trapezoid.
3. When you substitute the values, you obtain:
(5x-3)=[(6x-1)+3]/2
4. Now, you can solve the problem by clearing the "x":
</span>
(5x-3)=[(6x-1)+3]/2
2(5x-3)=6x-1+3
10x-6=6x+2
10x-6x=2+6
4x=8
x=8/4
x=2
Answer:
The value of y would be 45.5
Step-by-step explanation:
To solve this problem, start with the base form of direct variation.
y = kx
Now we can use our original values to model the equation and find k.
35 = k(2.5)
14 = k
Now we can model the equation as:
y = 14x
Now to find y, when x = 3.25, simply put 3.25 into the equation.
y = 14(3.25)
y = 45.5
<h3>Answer:</h3>
D
<h3>Explanation:</h3>
The graph of |x| opens upward. Your graph is vertically stretched by a factor of 3 and translated downward 1 unit.
Graphs B and D open upward, but only graph D is translated downward (not upward, as in B).
The second one, fourth one, and sixth one are true.
Hope this helps!
Answer:
2^5>4^2
Step-by-step explanation:
hopefully this makes sense
:)
