Okay so I am going to summarize the work out process because its a lot to
Here we go
1/3 (t) + 3/4 - 2/4 - t = ?
1/2 (simplify )
(1/3 (T)+3/4 - 1/2 - (t) = ?
t (2) / 2
1 - 2(t) / 2 = ?
3/4 (simplify this )
1/3(t)+ 3/4 - [1 - 2(t) / 2 = ?
1/3 (this is re last one you have to simplify)
L (Denominator): 3
R (Denominator): 4
L: [L.C.M] : 4
R: [L.C.M] : 3
Basically , we just switched the dominators around
So, Therefore The of t is -3/16
T = -3/16
Answer:
Step-by-step explanation:
We are given that:
And we want to find F'(0).
First, find F(x):
![\displaystyle F'(x) = \frac{d}{dx}\left[ f(3x)]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20F%27%28x%29%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5Cleft%5B%20f%283x%29%5D)
From the chain rule:
![\displaystyle \begin{aligned} F'(x) &= f'(3x) \cdot \frac{d}{dx} \left[ 3x\right] \\ \\ &= 3f'(3x)\end{aligned}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cbegin%7Baligned%7D%20F%27%28x%29%20%26%3D%20f%27%283x%29%20%5Ccdot%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5Cleft%5B%203x%5Cright%5D%20%5C%5C%20%5C%5C%20%26%3D%203f%27%283x%29%5Cend%7Baligned%7D)
Then:
In conclusion, F'(0) = 15.
Answer:
Step-by-step explanation:
<u>The balls - multiples of 3 are:</u>
<u>The probability of a multiple of 3 is:</u>
- 3 out of 10 or
- P = 3/10 = 30%
30% probability is in the range 0%-50% so this event is unlikely
Length from R(-2, 4) to S(3, 4) is sqrt((3 - (-2))^2 + (4 - 4)^2) = sqrt(5)^2 = 5 units
Length from S(3, 4) to T(3, -1) is sqrt((3 - 3)^2 + (-1 - 4)^2) = sqrt(-5)^2 = 5 units
Therefore, total length = 5 + 5 = 10 units.
