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Fudgin [204]
3 years ago
5

The side of an equilateral triangle is 8 inches shorter than the side of a square. The perimeter of the square is 46 inches more

than the perimeter of the triangle. Find the length of a side of the square
Mathematics
1 answer:
Juliette [100K]3 years ago
5 0
The perimeter<span> of an </span>equilateral triangle<span> is 7 </span>inches more than<span> the </span>perimeter<span> of a </span>square<span>, and the </span>side<span> of the </span>triangle<span> is 5 </span>inches<span> longer </span>than<span> the </span>side<span> of the </span>square<span>. </span>Find<span> the </span>side of the triangle<span>. (Hint: An </span>equilateral triangle<span> has three </span>sides the same length<span>.</span>
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3 years ago
Solve the system of equations algebraically. 4x-3y=8 5x-4y=5
baherus [9]

Answer:

x= 17 and y=20

Step-by-step explanation:

4x- 3y= 8-------1

5x-4y= 5-------2

Subtracting 2 from 1

5x-4y= 5

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x-y=-3----------3

From 3 we have x= y-3-------4

Putting 4 in 1

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3 0
4 years ago
3. The length of a rectangle is 4 inches more than its width. The area of the rectangle is equal to 5 inches more than 2 times t
Oksana_A [137]
Answer:
Length: sqrt13 + 4
Width: sqrt13
Step-by-step explanation:
Denote the width as x, then the length is x+4. The area of the rectangle will be x(x+4), and the perimeter will then be 4x +8. Hence, you can write the equation x(x+4) - 5 = 4x+8. Solving, you get x = sqrt13.
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3 years ago
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Answer:

34.2

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