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Brums [2.3K]
3 years ago
10

HELPPPPPP!!!!!!!!PLSSSS!!!!!!!

Mathematics
2 answers:
Luda [366]3 years ago
8 0

Answer:

c

Step-by-step explanation:

kozerog [31]3 years ago
5 0

Answer:

c

Step-by-step explanation:

just took it.

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What is the sqaure root of 2309!!!??
Serggg [28]

Answer:

the answer is approximately 48.05.

Step-by-step explanation: You can either use a calculator or estimate knowing that 50 is the square root of 2500, which is slightly above 2309. You can also use differentials and calculus to find an approximation.

3 0
2 years ago
Read 2 more answers
In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
Armando is baking 36 batches of brownies for the bake sale. Each batch of brownies takes cups of flour. What is a reasonable est
Goshia [24]

Answer:

Well, let's assume that "cups" = 3 cups of flour.

Step-by-step explanation:

First, multiply 3x36.

If for some reason this is incorrect, try 2 cups instead of 3. Both are reasonable measurements when it comes to baking.

8 0
3 years ago
Please answer within 7 minutes !!
Gnesinka [82]

Step-by-step explanation:

x = by - 3/2

x + 3/2 = by

y = x/b + 3/(2b)

now compare this to the first equation :

y = 2x + 3

the system has infinite solutions, if both equations are actually identical.

and they are only identical, if b = 1/2

y = x/(1/2) + 3/(2 × 1/2) = 2x + 3

3 0
2 years ago
An empty 6-gal water jug weighs 0.5 lb. With 3 c of water inside, the jug weighs 2 lb. Which equation models the jug’s weight y
nikdorinn [45]
The slope would be 2/3 because that would leave pounds when multiplied by cups.

add 0.5 for the weight of the water jug

y = (2/3)x + 0.5
3 0
3 years ago
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