9514 1404 393
Answer:
C) ΔDCE ≅ ΔDQR
Step-by-step explanation:
Corresponding vertices can be identified by the number of arcs signifying congruence.
1 mark: angles D and D
2 marks: angles C and Q
3 marks: angles E and R
Corresponding angles are listed in the same order in the congruence statement:
ΔDCE ≅ ΔDQR
<span>Formula: H(t) = 56t – 16t^2
</span>
H(t) = - 16t^2 + 56t
<span><span>A.
</span>What is the height of the ball after 1 second? H
(1) = 56(1) – 16(1) ^2 = 40 pt.</span>
<span><span>B.
</span>What is the maximum height? X = - (56)/2(- 16) =
1.75 sec h (1.75) = 56(1.75) – 16(1.75) ^2 h (1.75) = 49ft.</span>
<span><span>C.
</span><span>After how many seconds will it return to the
ground? – 16t^2 + 56t = 0 - 8t =0 t = 0</span></span>
<span><span>-
</span><span>8t (2 + - 7) = 0 2t – 7 = 0 t = 7/2
Ans: 3.5 seconds</span></span>
Answer:
the answer will be 21/50
Step-by-step explanation:
Convert to a fraction by placing the expression over 100
21/50
Answer:
(Answer D)
Step-by-step explanation:
Please use " ^ " to indicate exponentiation: y = -8x^2 - 2, y = -8x^2
The graph of y = -8x^2 is an inverted parabola with vertex at (0, 0).
That of y = -8x^2 - 2 is the same as above, except that the whole graph has been shifted 2 units down (Answer D).
So for example B(4,1) so x=4, y=1
->B'(4-2,1-4)
->B'(2,-3)
->A'(1-2,1-4)
->A'(-1,-3)
->C'(4-1,-2-4)
->C'(3,-6)
->D'(1-2,-2-4)
->D'(-1,-6)
so the image of the rectangle ABCD->A'B'C'D'
