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Andre45 [30]
3 years ago
8

If you mixed 5.50 mL of the acidic solution with 6.79 mL of the basic solution, what should be the pH of the resulting solution?

Report your answer with 3 decimal places. Note: The pKa for acetic acid is 4.757. The activity coefficients for acetic acid and the acetate ion are 1.000 and 0.775, respectively, in a solution with an ionic strength of 0.10 M.
Chemistry
1 answer:
Dima020 [189]3 years ago
7 0

Answer : The  pH of the resulting solution is 4.6

Explanation : Given,

pK_a=4.757

Activity coefficient for acetic acid = 1.000

Activity coefficient for acetate ion = 0.775

Ionic strength = 0.10 M

To calculate the pH of resulting solution we are  using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

Now put all the given values in this expression, we get:

pH=4.757+\log (\frac{0.775\times 0.10}{1.000\times 0.10})

pH=4.6

Thus, the pH of the resulting solution is 4.6

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Which of the following isoelectronic series is correctly ranked from largest ionic radius to smallest ionic radius? 1. N 3−, O 2
love history [14]

Answer:

<u>Option 1</u>:  N⁻³ > O⁻² > F⁻ > Na⁺ > Mg⁺²    

Explanation:

<u>Ionic radius is the radius of an atom´s ion in ionic crystal structure</u>.<u> </u><u><em>In an ion that lose an electron, to form a cation, the radius of the ion gets smaller</em></u><em>, </em>because the repulsion between electrons decrease because fewer electrons are present. Conversely, <u><em>adding on electron to a neutral atom, to form an anion, causes electron - electron repulsions to increase, so the size of the radius of the ion gets bigger.</em></u>                  

<u><em>Isoelectronic species are ions or elements that have the same number of electrons in their electronic shells but have different overall charges, because of their different atomic numbers</em></u>.                        

<u><em>In a isolelectronic series (same number of electrons),</em></u> <u><em>the increase of the positive charge (given by the number of protons in the nucleus), will cause a decrease in radius </em></u>beacuse the greater electrostatic attraction between the electrons and the nucleus. Consequently, the ion with the greatest nuclear charge will have the smallest ionic radius and the ion with the smallest nulear charge will have the largest ionic radius.  

<u>We will use this principle to solve our problem</u>.  

In our case, the given ions are:  

  • N⁻³ :    Z = 7,  e⁻ = 10
  • O⁻²:     Z= 8,   e⁻ =10
  • F⁻:       Z = 9,  e⁻ = 10
  • Na⁺:    Z= 11,   e⁻ = 10
  • Mg⁺²:  Z=12,   e⁻ =10

where Z= number of protons, and e⁻ = number of electrons.

<em><u>Hence the decreasing order of ionic radius is:</u></em>

N⁻³ > O⁻² > F⁻ > Na⁺ > Mg⁺²  

Have a nice day!

4 0
3 years ago
Based on this reaction, find how many moles of co can be obtained starting with 7 mol ch4?
Klio2033 [76]
I will solve the question assuming the reaction used as below
1 CH4(g) + 1 H2O(g) ==> 1 CO(g) + 3 H<span>2(g)

In the reaction, CH4 is the reactant and CO is the wanted product. If you look at the coefficient of the substance, for every 1 mol of CH4 react there will be 1 mol of CO produced. So, if you have 7 moles of CH4 the amount of CO produced would be: 7 moles * 1/1= 7 moles of CO</span>
5 0
4 years ago
Read 2 more answers
At what time of day are dissolved oxygen levels most likely to be highest? A. 6:00 AM B. 12:00 PM (noon) C. 6:00 PM D. 12:00 AM
Lunna [17]
It's C - 6:00PM. 

C - 6:00PM
4 0
4 years ago
Read 2 more answers
Assuming constant pressure and temperature, how many moles of gas have been added to the initial 3 moles of gas when the volume
puteri [66]
The answer is 3 moles
3 0
3 years ago
I NEED HELP PLEASE! :)
riadik2000 [5.3K]

Answer:

C_{21} H_{23} NO_{5}

Explanation:

First thing is we have assume all the percents are grams so we have

68.279g C, 6.2760g H, 3.7898g N, and 21.656g O

Now convert each gram to moles by dividing the the molar mass of each element

68.279g/12.01g= 5.685 moles of C

6.2760g/1.01g= 6.214 moles of H

3.7898g N/14.01g= 0.271 moles  of N

21.656g O/ 16.00g= 1.354 moles of O

Now to find the lowest ratios divide all the moles by the smallest number of moles you found, in our case, the smallest moles is 0.271 moles of N so divide everything by that....

5.685 moles/0.271 moles ------> ~21 C

6.214 moles/0.271 moles --------> ~23 H

0.271 moles  / 0.271 moles  ---------> 1 N

1.354 moles/ 0.271 moles ----------> ~5 O

So the empirical formula is C21H23NO5 C_{21} H_{23} NO_{5}

5 0
3 years ago
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