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Mama L [17]
3 years ago
10

Hydrogen gas was cooled from 150 K to 50 K. Its new volume (V2) is 75 mL. What was its original volume (V1)?

Chemistry
2 answers:
Nostrana [21]3 years ago
6 0

Explanation:

57.3ml

we use Charles's law

to solve the question

Leokris [45]3 years ago
4 0

Answer:

\boxed {\boxed {\sf 225 \ mL}}

Explanation:

The temperature and volume of the gas are changing, so we use Charles's Law. This states the temperature of a gas is directly proportional to the volume of a gas. The formula is:

\frac{V_1}{T_1}=\frac{V_2}{T_2}

The original volume is unknown. The new volume is 75 milliliters.

The gas is cooled from 150 Kelvin to 50 Kelvin, so the original temperature is 150 K and the new temperature is 50 K.

We know that:

  • T₁= 150 K
  • V₂= 75 mL
  • T₂= 50 K

Substitute the values into the formula.

\frac {V_1}{150 \ K}=\frac{ 75 \ mL}{50 \ K}

Since we are solving for the original volume, we must isolate the variable V₁.

It is being divided by 150 K. The inverse of division is multiplication, so we multiply both sides by 150 K.

150 \ K *\frac {V_1}{150 \ K}=\frac{ 75 \ mL}{50 \ K}* 150 \ K

V_1=\frac{ 75 \ mL}{50 \ K}* 150 \ K

The units of Kelvin (K) cancel.

V_1= \frac{ 75 \ mL}{50 }* 150

V_1=1.5 * 150 \ mL

V_1= 225 \ mL

The original volume is <u>225 milliliters.</u>

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