Find the quotient of the following decimals 4.68 / 1.8 *

Which expression is equivalent to

nirvana33 [79]

For this case, we must find an expression equivalent to:

$\frac {-9x ^ {- 1} y ^ {- 9}} {- 15x ^ 5y ^ {- 3}}$

By definition of power properties we have:

$a ^ {- 1} = \frac {1} {a ^ 1} = \frac {1} {a}$

Rewriting the previous expression we have:

The "-" are canceled and we take into account that:

$\frac {9} {15} = \frac {3} {5}$

So:

$\frac {3} {5x^5 * x ^ 1 *y ^ 9* y ^ {- 3}} =$

According to one of the properties of powers of the same base, we must put the same base and add the exponents:

$\frac {3} {5x ^ {5 + 1} * y ^ {9-3}} =\\\frac {3} {5x ^ 6 * y ^ 6}$

Answer:

$\frac {3} {5x ^ 6 * y ^ 6}$

Option B

3 0

3 years ago

Read 2 more answers

Suppose that 35% of all voters voted for a recall. Find the mean of the sampling distribution of the proportion of the 3150 peop

Aloiza [94]

Answer:

0.35 is the mean of the sampling distribution of the proportion.

Step-by-step explanation:

We are given the following in the question:

Percentage of voters who voted for recall = 35%

$p = 35\% = 0.35$

Sample size, n = 3150

We have to find the mean of the sampling distribution.

Formula for mean of sampling distribution:

$\mu = p$

Putting values, we get,

$\mu = 0.35$

Thus, 0.35 is the mean of the sampling distribution of people sampled in an exit poll who voted for the recall.

8 0

3 years ago

The student council is selling tickets to a school dance. One teacher decides to pay $10 for his class, and the students in the

Lostsunrise [7]

Hi,

x + y = 350 (equation 1)

3x + 2y = 950 (equation 2)

Use Substitution Method

Isolate variable x in equation 1

x = 350 – y (equation 3)

Substitute equation 3 into equation 2

3(350 – y) + 2y = 950

1050 – 3y + 2y = 950

3y – 2y = 1050 – 950

y = 100

Substitute y = 100 into equation 1

x + 100 = 350

x = 250

Answer: 250 $3 tickets and 100 $2 tickets were sold.

8 0

3 years ago

Suppose that we don't have a formula for g(x) but we know that g(3) = −5 and g'(x) = x2 + 7 for all x. (

True [87]

So it tells us that g(3) = -5 and g'(x) = x^2 + 7.

So g(3) = -5 is the point (3, -5)
Using linear approximation
g(2.99) is the point (2.99, g(3) + g'(3)*(2.99-3))

now we just need to simplify that
(2.99, -5 + (16)*(-.01)) which is (2.99, -5 + -.16) which is (2.99, -5.16)
So g(2.99) = -5.16

Doing the same thing for the other g(3.01)
(3.01, g(3) + g'(3)*(3.01-3))
(3.01, -5 + 16*.01) which is (3.01, -4.84)
So g(3.01) = -4.84

So we have our linear approximation for the two.

If you wanted to, you could check your answer by finding g(x). Since you know g'(x), take the antiderivative and we will get
g(x) = 1/3x^3 + 7x + C
Since we know g(3) = -5, we can use that to solve for C
1/3(3)^3 + 7(3) + C = -5 and we find that C = -35
so that means g(x) = (x^3)/3 + 7x - 35

So just to check our linear approximations use that to find g(2.99) and g(3.01)

g(2.99) = -5.1597
g(3.01) = -4.8397

So as you can see, using the linear approximation we got our answers as
g(2.99) = -5.16
g(3.01) = -4.84
which are both really close to the actual answer. Not a bad method if you ever need to use it.

5 0

3 years ago

Please enter the missing number: 2, 9, 20, 37, 64, 107, ?

k0ka [10]

174 is the missing number

4 0

3 years ago