Using derivatives, it is found that:
i) 
ii) 9 m/s.
iii) 
iv) 6 m/s².
v) 1 second.
<h3>What is the role of derivatives in the relation between acceleration, velocity and position?</h3>
- The velocity is the derivative of the position.
- The acceleration is the derivative of the velocity.
In this problem, the position is:

item i:
Velocity is the <u>derivative of the position</u>, hence:

Item ii:

The speed is of 9 m/s.
Item iii:
Derivative of the velocity, hence:

Item iv:

The acceleration is of 6 m/s².
Item v:
t for which a(t) = 0, hence:




Hence 1 second.
You can learn more about derivatives at brainly.com/question/14800626
Answer:
-111
Step-by-step explanation:
substitute 5 in place of each x
-4(5)^2 - 3(5) + 4
then evaluate or type it into your calculator
-100 - 15 + 4
Answer:
c.
Step-by-step explanation:
i actually dont know i just guessed
Answer:
Y = 4/3x + 0
Step-by-step explanation:
(-3,-4) and (3,4) can be plugged in to rise over run.
y 4 -(-4) = 8
x 3 - (-3) = 6
8/6 = 4/3
Plug into slope intercept form
4 = 4/3(3) + b
4 = 12/3 +b
4 = 4 +b
Subtract from both sides
0 = b
Y = 4/3x + 0
14+5(x+3)-7
14+(5x+15)-7
7+5x+15
5x+22