Question

Solve the quadratic by factoring. x^2-5x-31=5

Answer 1

Answer:

$x = - 4\: or \: x = 9$

Step-by-step explanation:

make one side equal to zero:

${x}^{2} - 5x - 36 = 0$

find two factors that multiply to -36 and add to -5 (-9 & 4)

${x }^{2} - 9x + 4x - 36 = 0$

factorise

$x(x - 9) + 4(x - 9) = 0$

$(x + 4)(x - 9) = 0$

solve for x

$x = - 4 \: or \: x = 9$