Question

b] In the opposite figure : XYZL is a square, XZ = 10 cm. , m(L XZY) = 43° Calculate the perimeter of triangle XYZ ​

Answer 1

Answer:

Perimeter of Δ XYZ = 24.13

Step-by-step explanation:

In Δ XYZ is a right  triangle because the XYZL is a square.  Therefore the hypotenuse = 10; Looking at the 43° angle, XY is the side that is opposite the 43° angle and the YZ is the side that is adjacent to the 43°.

Using the trig ratios:  

XY = opposite/ hypotenuse which is Sin 43°

Sin 43° = XY/ 10

10(Sin 43°) = XY

 6.82 = XY

YZ = adjacent/hypotenuse which is Cos 43°

Cos 43° = YZ/10

10(cos 43°) = YZ

7.31 = YZ

Now the Perimeter = XY + YZ + XZ

  Perimeter = 6.82 + 7.31 + 10

  Perimeter = 24.13