If the standard deviation of an exam is 5, the z-score us 1.95 and the mean is 80, the actual test score is; 89.75
<h3>How to solve z-score problems?</h3>
We are given;
Standard deviation; s = 5
z-score = 1.95
Mean = 80
Formula for z-score is;
z = (x' - μ)/σ
Thus;
1.95 = (x' - 80)/5
1.95 * 5 = (x' - 80)
9.75 = x' - 80
x' = 80 + 9.75
x' = 89.75
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The result you get when you divide is 11 + 16/x + 1
Answer:
10. 7n - 1 < -8
Isolate the variable, n. Do the opposite of PEMDAS. Treat the < as equal sign, what you do to one side, you do to the other. First, add 1 to both sides:
7n - 1 (+1) < - 8 (+1)
7n < - 8 + 1
7n < - 7
Isolate the variable, n. Divide 7 from both sides:
(7n)/7 < (-7)/7
n < -7/7
n < -1
n < -1 is your answer.
11. 3 > -7v + 4v
Combine like terms, then isolate the variable, v. First, add -7v and 4v together.
3 > (-7v + 4v)
3 > (4v - 7v)
3 > (-3v)
Isolate the variable, v. Divide -3 from both sides. Note that since you are dividing a negative number, you must flip the sign:
(3)/-3 > (-3v)/-3
3/-3 > v
-1 < v
v > -1 is your answer.
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Answer:
1,2,3
Step-by-step explanation:
