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blsea [12.9K]
3 years ago
7

Number 4 please !! due tomorrow

Mathematics
1 answer:
Minchanka [31]3 years ago
4 0

Answer:

c is the answer




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An astronaut who weighs 174 lb on Earth weighs 29 lb on the moon. Which of the following are correct amounts for weight on Earth
Korolek [52]

174/29 = 6 times the difference

17*6 = 102


12*6= 72

34*6 =204

15*6 = 90


so the answer is A

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3 years ago
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50 POINTS !!<br><br><br> PLEASE HELP !! ILL GIVE BRAINLIEST TO THE RIGHT ANSWERS.
Artyom0805 [142]

Answer:

12

Step-by-step explanation:

Use the pythagorean theorem (a^2+b^2=c^2). A and b are the two legs of the triangle, and c is ALWAYS the hypotenuse. Plug in the values for a and c

a^2+b^2=c^2

5^2+b^2=13^2

25+b^2=169

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3 years ago
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If I drive at `70` miles per hour, my journey will take `2.5` hours. How long will my journey take if I drive at `60` miles per
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Step-by-step explanation:

7 0
3 years ago
Find the sum of all positive integers less than 200 that are divisible by 7.
Troyanec [42]

Step-by-step explanation:

the positive integer numbers that are divisible by 7 are an arithmetic sequence by always adding 7 :

a1 = 7

a2 = a1 + 7 = 7+7 = 14

a3 = a2 + 7 = a1 + 7 + 7 = 7 + 2×7 = 21

...

an = a1 + (n-1)×7 = 7 + (n-1)×7 = n×7

the sum of an arithmetic sequence is

n/2 × (2a1 + (n - 1)×d)

with a1 being the first term (in our case 7).

d being the common difference from term to term (in our case 7).

how many terms (what is n) do we need to add ?

we need to find n, where the sequence reaches 200.

200 = n×7

n = 200/7 = 28.57142857...

so, with n = 29 we would get a number higher than 200.

so, n=28 gives us the last number divisible by 7 that is smaller than 200 (28×7 = 196).

the sum of all positive integers below 200 that are divisible by 7 is then

28/2 × (2×7 + 27×7) = 14 × 29×7 = 2,842

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2 years ago
Rachel buys a new television that is on sale for 15% off. She also gets a 5% discount on the sale price plus a $50 mail-in rebat
Minchanka [31]
$ 2372.50 is  the final amount that Rachel will have to pay.
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3 years ago
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