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blsea [12.9K]
3 years ago
7

Number 4 please !! due tomorrow

Mathematics
1 answer:
Minchanka [31]3 years ago
4 0

Answer:

c is the answer




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Use the equation y = q + 3 to find the value of y when q = 1.
nikitadnepr [17]

Answer:

It’s 4

Step-by-step explanation:

8 0
3 years ago
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F(0)=4-8x indicate value
Luba_88 [7]
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f(0)=4-8(0)
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Simplify the expression 4x^3/28x^4
KIM [24]
1/7x

Factorize the numbers (4 and 28) as they have a common factor of 4 so you can simplify it to 1/7. Cancel out the 3 in the x (numerator) from the denominator and you will have x^1 remaining in the denominator. That is also the same as x, therefore making it 1/(7x)
5 0
3 years ago
3) PLEASE HELP WITH THIS QUESTION!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1
Snowcat [4.5K]
The vertical asymptote is the located in the denominator, so (x-4)=0, x=4, the asymptote is x=4, and the limit is negative infinity 
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3 years ago
M=(N-2)/N solve for N
Tpy6a [65]

M = (N-2)/N

M = N² - 2N

N² - 2N - M = 0

To find N we need to use quadratic formula.

For our equation x = N, a=1, b= -2, c= -M

x=\frac{-b+/-\sqrt{b^{2}-4ac} }{2a}
\\ \\N=\frac{-(-2)+/-\sqrt{(-2)^{2} -4*1*(-M)} }{2*1}
\\ \\ N=\frac{2+/-\sqrt{4+4M} }{2} \\ \\ N=\frac{-2+/-2\sqrt{1+M} }{2} = -1+/-\sqrt{1+M} \\ \\ N = -1 +\sqrt{1+M} \ or\ N=-1-\sqrt{1+M}


4 0
3 years ago
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