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Leni [432]
2 years ago
5

Let f(x)=-3x+4. describe the transformation from the graph of f to the graphs g(x) and f(x)+3 and h(x)-f(x-2)

Mathematics
2 answers:
Liula [17]2 years ago
8 0

Answer:

Answer:

g(x)=-6/5x+1/2

h(x)=-6/5x-1/2

Step-by-step explanation:

1).   g(x)=−f(x) ?

f(x)=6/5x−1/2

g(x)=−(6/5x−1/2)

g(x)=-6/5x+1/2

2). h(x)=f(−x) ?

f(-x)=6/5(-x)−1/2

f(-x)=-6/5x-1/2

h(x)=-6/5x-1/2

Nesterboy [21]2 years ago
6 0

Step-by-step explanation:

I don't know the words used in the answer options.

but what happens is

g(x) = f(x) + 3

you know, what the result of a function stand for ? the y value or coordinate.

g(x) is still the original f(x) in shape and size. but the resulting y is additionally increased by 3 consistently.

so, as result, the whole graph of f(x) moves up vertically by 3 units compared to the original f(x) graph.

h(x) = f(x - 2)

again, h(x) is still the original f(x) in shape and size. but now we are creating y values not for x itself but for an x value that is 2 units "before" the actual x value (in the sense when moving along the graph from left to right).

so, as result, the whole graph of f(x) moves right horizontally by 2 units compared to the original f(x) graph.

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Determine the equation of the line that passes through the points of intersection of the graphs of the quadratic functions f(x)
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Step-by-step explanation:

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Equation of line passing through two points \left ( x_1,y_1 \right )\,,\,\left ( x_2,y_2 \right ) is given by y-y_1=\frac{y_2-y_1}{x_2-x_1}\left ( x-x_1 \right )

Let \left ( x_1,y_1 \right )=\left ( 2,0 \right )\,,\,\left ( x_2,y_2 \right )=\left ( -1.5,-1.75\ \right )

So, equation is as follows :

y-0=\frac{-1.75-0}{-1.5-2}\left ( x-2 \right )\\y=\frac{-1.75}{-3.5}\left ( x-2 \right )\\y=\frac{1}{2}(x-2)\\2y=x-2\\x-2y-2=0

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