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Leni [432]
2 years ago
5

Let f(x)=-3x+4. describe the transformation from the graph of f to the graphs g(x) and f(x)+3 and h(x)-f(x-2)

Mathematics
2 answers:
Liula [17]2 years ago
8 0

Answer:

Answer:

g(x)=-6/5x+1/2

h(x)=-6/5x-1/2

Step-by-step explanation:

1).   g(x)=−f(x) ?

f(x)=6/5x−1/2

g(x)=−(6/5x−1/2)

g(x)=-6/5x+1/2

2). h(x)=f(−x) ?

f(-x)=6/5(-x)−1/2

f(-x)=-6/5x-1/2

h(x)=-6/5x-1/2

Nesterboy [21]2 years ago
6 0

Step-by-step explanation:

I don't know the words used in the answer options.

but what happens is

g(x) = f(x) + 3

you know, what the result of a function stand for ? the y value or coordinate.

g(x) is still the original f(x) in shape and size. but the resulting y is additionally increased by 3 consistently.

so, as result, the whole graph of f(x) moves up vertically by 3 units compared to the original f(x) graph.

h(x) = f(x - 2)

again, h(x) is still the original f(x) in shape and size. but now we are creating y values not for x itself but for an x value that is 2 units "before" the actual x value (in the sense when moving along the graph from left to right).

so, as result, the whole graph of f(x) moves right horizontally by 2 units compared to the original f(x) graph.

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Are there any linear quantities in the chart shown? And if so, what is the slope of said pairs?
VashaNatasha [74]

The chart does not represent a linear quantity

<h3>How to determine if there are linear quantities in the chart shown?</h3>

From the chart, we have the following coordinates

(x, y) = (0.10, 0.14), (0.50, 0.32), (1.00, 0.46), (1.70, 0.59) and (2.00, 0.63)

To determine if the chart is a linear quantity, we simply calculate the slope using the coordinates.

The slope is calculated as:

m = (y2 - y1)/(x2 - x1)

So, we have:

m = (0.32 - 0.14)/(0.50 - 0.10) = 0.45

m = (0.46 - 0.32)/(1.00 - 0.50) = 0.28

In the above computations, the calculated slopes are not equal

Hence, the chart does not represent a linear quantity

Read more about linear equations at:

brainly.com/question/1884491

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7 0
2 years ago
The starting numbers for x and y are already entered in a table below the blanks in the table represent the next two terms for e
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Answer:

it is this one

Step-by-step explanation:

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3 years ago
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Answer:

We have: g(x)=(x+2)(x-1)(x-2)

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This is a polynimial function with 2 vertices

The roots are approximatively:

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their images are:

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Answer:

\boxed{y=1}

Step-by-step explanation:

Since m\angle1=m\angle2 due to \over{VP} is an angle bisector, we have the following:

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